Python 用字典值替换字符串

Question

基于给定的输入:

I can do waaaaaaaaaaaaay better :DDDD!!!! I am sooooooooo exicted about it :))) Good !!

期望:输出

I can do way/LNG better :D/LNG !/LNG I am so/LNG exicted about it :)/LNG Good !/LNG

--- 挑战:

1. 更好 vs. sooooooooooo >> 我们需要保持第一个不变，但缩短第二个
2. 对于第二个，我们需要添加一个标签(LNG)，因为它可能对于强化主观性和情感具有一定的重要性

---- 问题:错误消息“不平衡括号”

有什么想法吗？

我的代码是:

import re 

lengWords = {} # a dictionary of lengthened words 

def removeDuplicates(corpus):

data = (open(corpus, 'r').read()).split()
myString = " ".join(data)

for word in data:
    for chr in word: 
        countChr = word.count(chr)
        if countChr >= 3: 
            lengWords[word] = word+"/LNG"
            lengWords[word] = re.sub(r'([A-Za-z])\1+', r'\1', lengWords[word])
            lengWords[word] = re.sub(r'([\'\!\~\.\?\,\.,\),\(])\1+', r'\1', lengWords[word])                             

    for k, v in lengWords.items():
        if k == word: 
            re.sub(word, v, myString)
return myString

Answer 1

这不是完美的解决方案，但我现在没有时间改进它 - 只是想让您以简单的方法开始:

s = "I can do waaaaaaaaaaaaay better :DDDD!!!! I am sooooooooo exicted about it :))) Good !!"
re.sub(r'(.)(\1{2,})',r'\1/LNG',s)
>> 'I can do wa/LNGy better :D/LNG!/LNG I am so/LNG exicted about it :)/LNG Good !!'