c# - 在循环 C# 中编写 XML

Question

我将如何写出 xml

<?xml version="1.0" encoding="UTF-8"?>
<calibration>
  <ZoomLevel 250>0.0100502512562814</ZoomLevel 250>
  <ZoomLevel 250>0.0100502512562814</ZoomLevel 250>
  ........
</calibration>

我知道如何写出来，但我不能在一个循环中写出来，我需要自动取款机，我有用于编写 xml 表的是

public void XMLWrite(Dictionary<string, double> dict)
{
    //write the dictonary into an xml file
    XmlDocument doc = new XmlDocument();
    XmlNode docNode = doc.CreateXmlDeclaration("1.0", "UTF-8", null);
    doc.AppendChild(docNode);

    XmlNode productsNode = doc.CreateElement("calibration");
    doc.AppendChild(productsNode);

    foreach (KeyValuePair<string, double> entry in dict)
    {
        XmlNode zoomNode = doc.CreateElement("ZoomLevel");

        XmlAttribute ZoomLevel = doc.CreateAttribute(entry.Key.ToString());
        //XmlElement PixelSize = doc.CreateElement (entry.key = entry.Value.ToString());
        zoomNode.Attributes.Append(ZoomLevel);

        productsNode.AppendChild(zoomNode);
    }
    doc.Save(pathName);
}

Answer 1

正如其他人所说，您想要的 xml 无效。我注意到的另一件事是，在您的示例中，有两个节点的缩放级别为 250，这是字典的键，正如您所知，它应该是唯一。但是，我建议您使用更简单的 LINQ to XML (System.Xml.Linq)，那么:

public void XMLWrite( Dictionary<string, double> dict ) {
   //LINQ to XML
   XDocument doc = new XDocument( new XElement( "calibration" ) );

   foreach ( KeyValuePair<string, double> entry in dict )
     doc.Root.Add( new XElement( "zoom", entry.Value.ToString( ), new XAttribute( "level", entry.Key.ToString( ) ) ) );

   doc.Save( pathName );
}

我通过这个字典测试了这段代码:

"250", 0.110050251256281
"150", 0.810050256425628
"850", 0.701005025125628
"550", 0.910050251256281

结果是:

<?xml version="1.0" encoding="utf-8"?>
<calibration>
  <zoom level="250">0,110050251256281</zoom>
  <zoom level="150">0,810050256425628</zoom>
  <zoom level="850">0,701005025125628</zoom>
  <zoom level="550">0,910050251256281</zoom>
</calibration>