python 正则表达式模式在字符串中不匹配，甚至在测试器中匹配(重试，正则表达式教练，http ://ksamuel. pythonanywhere.com)

Question

我已经为我的目标构建了一个正则表达式模式:包含从 CSV 文件获取的数据的字符串。我在编程方面几乎完全是新手，但我真的陷入了这一步，并且我努力解决问题，因为正则表达式是(我认为......)解决我的问题的最佳选择，即是从 CSV 文件中搜索数据，它们之间存在一些差异，但其模式遵循正式协议(protocol)(MIAME 文件，来自生物信息学领域)。这是我的代码

import re
    ficheiro=open(raw_input('write the name of the file (formato CSV):'), 'r')
    lista_file=ficheiro.readlines()
    str_file=str(lista_file)
    list_spr=[]
    value_spr=[]
    for a in str_file:
        regex_spr = re.search(r"(spr[0-9]{4})[^\t.]*\t([0-9.]+)", a, re.I|re.M)
        print regex_spr.group()
        list_spr +=regex_spr.group(1)
        value_spr +=regex_spr.group(2)

但结果总是带有'NoneType'，例如

Traceback (most recent call last):
  File "C:\EDPython27\test\put_words_in_dict.py", line 112, in <module>
    print regex_spr.group()
AttributeError: 'NoneType' object has no attribute 'group'

接下来是我用来测试模式的 str_file 的一些范围:

('Reporter Identifier\tVALUE\n', 'spr0320060100000320\t4.784064198\n', 'spr0963060100000963\t3.646246197\n', 'spr1586060100001584\t5.755770215\n', 'spr1102060100001101\t5.794439261\n', 'spr1727060100001725\t6.452100774\n', 'spr0552060100000552\t6.816527711\n', 'spr0807060100000807\t3.185267941\n', 'spr0322060100000322\t5.889496662\n', 'spr0971060100000971\t3.112604228\n', 'spr0490060100000490\t6.608164616\n', 'spr0471060100000471\t6.807244139\n', 'spr0321060100000321\t5.331036948\n', 'spr1070060100001069\t6.408937689\n', 'spr1585060100001583\t6.157044216\n', 'spr1189060100001188\t3.481847857\n', 'spr1191060100001190\t3.523784616\n', 'spr1081060100001080\t6.708517655\n', 'spr1071060100001070\t7.092586967\n', 'spr1101060100001100\t6.294650154\n', 'spr0561060100000561\t7.52495517\n', 'spr0802060100000802\t8.299020685\n', 'spr1195060100001194\t6.143485258\n', 'spr0470060100000470\t5.869271803\n', 'spr1944060100001941\t7.060765363\n', 'spr0968060100000968\t6.276636704\n', 'spr1072060100001071\t7.267895537\n', 'spr0972060100000972\t5.535911422\n', 'spr1821060100001819\t7.660640949\n', 'spr0316060100000316\t6.399083059\n', 'spr0129060100000129\t6.693897057\n', 'spr0966060100000966\t6.208969299\n', 'spr0323060100000323\t6.230187159\n', 'spr1466060100001465\t7.609506586\n', 'spr0964060100000964\t6.286528191\n', 'spr1665060100001663\t5.597969101\n', 'spr0969060100000969\t5.122425278\n', 'spr1394060100001393\t7.310099682\n', 'spr0683060100000683\t7.397780719\n', 'spr1649060100001647\t6.121430945\n', 'spr0536060100000536\t7.936838283\n', 'spr1020060100001020\t7.339227818\n', 'spr0682060100000682\t7.435907739\n', 'spr0606060100000606\t6.251491879\n', 'spr0491060100000491\t5.400560984\n', 'spr0939060100000939\t6.928170725\n', 'spr1492060100001491\t7.451461913\n', 'spr0965060100000965\t5.610110186\n', 'spr1188060100001187\t3.384989187\n', 'spr1296060100001295\t5.927021756\n')

我提前感谢所有顾问。

Answer 1

来自docs关于re.search():

Scan through string looking for a location where the regular expression pattern produces a match, and return a corresponding MatchObject instance. Return None if no position in the string matches the pattern

因此，这里的解决方法是检查 regex_spr 是否为 None。

for a in str_file:
    regex_spr = re.search(r"(spr[0-9]{4})[^\t.]*\t([0-9.]+)", a, re.I|re.M)
    if regex_spr is not None:
        print regex_spr.group()
        list_spr +=regex_spr.group(1)
        value_spr +=regex_spr.group(2)
    else:
         #do something else