list - lisp 列表连接

Question

我如何编写一个函数，它有两个列表的参数并返回连接两个列表，不使用追加。

I know how to get the head of the second list but I don't know how to put it in the first one and what should I do if the head of the list is also a list.

Answer 1

是否允许使用 LOOP 或 DO？

像这样的东西会起作用:

(defun my-concat (x y)
  (loop 
    for o in (reverse x)
    do (push o y)
    finally (return y)))

如果循环不是一个选项，您可能想使用递归。