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python - 如何使用 PyQt Signal Slot 连接两个类?

转载 作者:太空宇宙 更新时间:2023-11-03 18:55:06 25 4
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我正在使用 Twisted 和 PyQt 在 Python 中编写一个应用程序。我想做的是,当客户端注册时,它会反射(reflect)在前端。因此,当服务器注册客户端时,它会发出一个信号,该信号将被捕获并触发一个插槽,但是,它似乎不起作用。代码中的两个信号槽均不起作用。

from PyQt4 import QtGui, QtCore
import sys
from twisted.internet.protocol import Factory, Protocol
from twisted.protocols import amp
import qt4reactor

class register_procedure(amp.Command):
arguments = [('MAC',amp.String()),
('IP',amp.String()),
('Computer_Name',amp.String()),
('OS',amp.String())
]
response = [('req_status', amp.String()),
('ALIGN_FUNCTION', amp.String()),
('ALIGN_Confirmation', amp.Integer()),
('Callback_offset',amp.Integer())
]

class Ui_MainWindow(QtGui.QMainWindow):

def __init__(self,reactor, parent=None):
super(Ui_MainWindow,self).__init__(parent)
self.reactor=reactor
self.pf = Factory()
self.pf.protocol = Protocol
self.reactor.listenTCP(3610, self.pf) # listen on port 1234

def setupUi(self,MainWindow):
MainWindow.setObjectName(_fromUtf8("MainWindow"))
MainWindow.resize(903, 677)
self.centralwidget = QtGui.QWidget(MainWindow)
sizePolicy = QtGui.QSizePolicy(QtGui.QSizePolicy.Expanding, QtGui.QSizePolicy.Expanding)
sizePolicy.setHorizontalStretch(0)
sizePolicy.setVerticalStretch(0)
sizePolicy.setHeightForWidth(self.centralwidget.sizePolicy().hasHeightForWidth())
self.centralwidget.setSizePolicy(sizePolicy)

self.create_item()


self.retranslateUi(MainWindow)
self.connect(self, QtCore.SIGNAL('triggered()'), self.closeEvent)
QtCore.QObject.connect(self,QtCore.SIGNAL('registered()'),self.registered)
QtCore.QMetaObject.connectSlotsByName(MainWindow)

def retranslateUi(self, MainWindow):
MainWindow.setWindowTitle(_translate("MainWindow", "MainWindow", None))
self.pushButton_4.setText(_translate("MainWindow", "Delete System ", None))
self.pushButton.setText(_translate("MainWindow", "Add System", None))
self.label_2.setText(_translate("MainWindow", "SYSTEM STATUS", None))
self.label.setText(_translate("MainWindow", "Monitoring Output", None))


def registered(self):# this function is not being triggered
print "check"
self.textbrowser.append()

def closeEvent(self, event):#neither is this being triggered
print "asdf"
self.rector.stop()
MainWindow.close()
event.accept()

class bridge(QtCore.QObject):
mySignal = QtCore.SIGNAL('mySignal(QString)')
def __init__(self):
QtCore.QObject.__init__(self)
def registered(self):
print "p op"
QtCore.QObject.emit(self, QtCore.SIGNAL('registered'))


class Protocol(amp.AMP):
@register_procedure.responder
def register_procedure(self,MAC,IP,Computer_Name,OS):
self.bridge_conn=bridge()
cursor_device.execute("""select * FROM devices where MAC = ?;""",[(MAC)])
exists_val=cursor_device.fetchone()
cursor_device.fetchone()
print "register"
if not exists_val== "":
cursor_device.execute("""update devices set IP= ? , Computer_name= ? , OS = ? where MAC= ?;""",[IP,Computer_Name,OS,MAC])
self.bridge_conn.registered() # <--emits signal
return {'req_status': "done" ,'ALIGN_FUNCTION':'none','ALIGN_Confirmation':0,'Callback_offset':call_offset(1)}
else:
cursor_device.execute("""INSERT INTO devices(Mac,Ip,Computer_name,Os) values (?,?,?,?);""",[MAC,IP,Computer_Name,OS])
self.bridge_conn.registered()#<--emits signal
return {'req_status': "done" ,'ALIGN_FUNCTION':'main_loop()','ALIGN_Confirmation':0,'Callback_offset':0}



if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)

try:
import qt4reactor
except ImportError:
from twisted.internet import qt4reactor
qt4reactor.install()

from twisted.internet import reactor
MainWindow = QtGui.QMainWindow() # <-- Instantiate QMainWindow object.
ui = Ui_MainWindow(reactor)
ui.setupUi(MainWindow)
MainWindow.show()
reactor.run()

最佳答案

这是我连接两个类的方法,我不知道这是最好的方法,但它按我想要的方式工作:

class MyForm(QtGui.QMainWindow):
def __init__(self):
....
self.connect(self, QtCore.SIGNAL("mySignal(PyQt_PyObject)"), self.doSomething)
....
def someMethod(self):
...
button = MyPushButton(i, self)
...
def doSomething(self):
...

class MyPushButton(QtGui.QPushButton):
def __init__(self, elementID, mForm):
super(MyPushButton, self).__init__()
self.__elementID = elementID
self.__mForm = mForm
self.connect(self, QtCore.SIGNAL('clicked()'), self, QtCore.SLOT("triggerOutput()"))

@QtCore.pyqtSlot()
def triggerOutput(self):
self.__mForm.emit(QtCore.SIGNAL("mySignal(PyQt_PyObject)"), self.__elementID)

所以,重要的是最后一行,我已从 MyPushButton 类 (self) 向 MyForm 类 (__mForm) 发出信号,并调用 doSomething() 。但正如您在这一行中看到的:button = MyPushButton(i, self),我已将 self (MyForm) 传递给 MyPushButton。

我希望这会对您有所帮助。

关于python - 如何使用 PyQt Signal Slot 连接两个类?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17451597/

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