C# 'Enumerable.Repeat()'如何重载？

Question

我为遗传算法编写了这段代码，该算法通过获取基因的随机整数(质量、(样本的)高度和腿部力量)来计算跳跃高度，然后用其他表现最好的随机数复制自身样本存储在名为 geneBoard 的二维数组中。现在我的问题；你看写出 1000 次相同的值是不切实际的，所以我尝试使用这个:

float[,] geneBoard = Enumerable.Repeat(
    mass = GetMass(500, 1000), 
    height = GetHeight(150, 190), 
    force = GetForce(500, 3500), 
    fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)), 1000)
.ToArray();

而不是这个:

float[,] geneBoard = new float[4, 4]
        {
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) }
        };

如果我没有做足够好的解释，这是我的所有代码:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Genetic_Algorithm
{
class Program
{
    static Random random = new Random(); // Getting a seed

    static void Main(string[] args)
    {


        float mass = GetMass(500, 1000);
        float height = GetHeight(150, 190);
        float force = GetForce(500, 3500);

        float fitnessScore = Convert.ToSingle( PhysicalTest(mass, height, force) );
        /*
        float[,] geneBoard = new float[4, 4]
        {
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) },
            { mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)) }
        };
        */
        float[,] geneBoard = Enumerable.Repeat(mass = GetMass(500, 1000), height = GetHeight(150, 190), force = GetForce(500, 3500), fitnessScore = Convert.ToSingle(PhysicalTest(mass, height, force)), 1000).ToArray();

        float[] sortingAr = new float[] { geneBoard[0, 3], geneBoard[1, 3], geneBoard[2, 3], geneBoard[3, 3] };
        Array.Sort(sortingAr, (x, y) => y.CompareTo(x));

        Console.WriteLine(sortingAr[0]);
        Console.WriteLine(sortingAr[1]);
    }

    public static float GetMass(int min, int max)
    {
        int massGr = random.Next(min, max);
        float mass = massGr / 10;

        return mass;
    }

    public static float GetHeight(int min, int max)
    {
        int heightCm = random.Next(min, max);
        float height = heightCm / 10;

        return height;
    }

    public static float GetForce(int min, int max)
    {
        int force = random.Next(min, max);

        return force;
    }

    public static double PhysicalTest(float mass, float height, float force)
    {
        double d = force * 0.07; // gets distance of applied force
        double vi = Math.Sqrt( (force * d) / ( mass / 2 ) ); // calculats v initial
        double jumpHeight = (vi * vi) / (2 * 9.8); // calculates jumping height

        double fitnessScore = jumpHeight * 100;

        return fitnessScore;
    }
}

最后，我是初学者，所以任何其他建议都会有所帮助。

Answer 1

我认为 Enumerable.Repeat 不是您真正想要的。正如它的名字所说，它只是一遍又一遍地重复相同元素，而在你的情况下，我认为你想要的是创建 1000 个相似但不同的对象代表你的基因。

在您的情况下，我想对您之前创建的数组进行简单的 for 循环就足够了。