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c# - Linq 对列表使用 Aggregate()

转载 作者:太空宇宙 更新时间:2023-11-03 18:48:48 25 4
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来自数据

OrderID     OrderAmt   OrderDate                                              
----------- ---------- --------------------
1 10.50 2003-10-11 08:00:00
2 11.50 2003-10-11 10:00:00
3 1.25 2003-10-11 12:00:00
4 100.57 2003-10-12 09:00:00
5 19.99 2003-10-12 11:00:00
6 47.14 2003-10-13 10:00:00
7 10.08 2003-10-13 12:00:00
8 7.50 2003-10-13 19:00:00
9 9.50 2003-10-13 21:00:00

我要显示以下运行总计

OrderId     OrderDate            OrderAmt   Running Total                        
----------- -------------------- ---------- -------------
1 2003-10-11 08:00:00 10.50 10.50
2 2003-10-11 10:00:00 11.50 22.00
3 2003-10-11 12:00:00 1.25 23.25
4 2003-10-12 09:00:00 100.57 123.82
5 2003-10-12 11:00:00 19.99 143.81
6 2003-10-13 10:00:00 47.14 190.95
7 2003-10-13 12:00:00 10.08 201.03
8 2003-10-13 19:00:00 7.50 208.53
9 2003-10-13 21:00:00 9.50 218.03

来自以下列表

List<OrderData> ord = new List<OrderData>();

ord.Add(new OrderData() { OrderNumber=1, OrderAmount=10.50,
OrderDate=new DateTime(2003,10,11)});

ord.Add(new OrderData() { OrderNumber=2, OrderAmount=11.50,
OrderDate=new DateTime(2003,10,11)});

ord.Add(new OrderData() { OrderNumber=3, OrderAmount=1.25,
OrderDate=new DateTime(2003,10,11)});

ord.Add(new OrderData() { OrderNumber=4, OrderAmount=100.57,
OrderDate =new DateTime(2003,10,12)});

ord.Add(new OrderData() { OrderNumber=5, OrderAmount=19.99,
OrderDate=new DateTime(2003,10,12)});

ord.Add(new OrderData() { OrderNumber=6, OrderAmount=47.14,
OrderDate =new DateTime(2003,10,13)});

ord.Add(new OrderData() { OrderNumber=7, OrderAmount=10.08,
OrderDate=new DateTime(2003,10,13)});

ord.Add(new OrderData() { OrderNumber=8, OrderAmount=7.50,
OrderDate=new DateTime(2003,10,13)});

ord.Add(new OrderData() { OrderNumber=9, OrderAmount=9.50,
OrderDate=new DateTime(2003,10,13)});

如何 reshape 以下查询

var query = from o in ord
select new
{
OrdNumber=o.OrderNumber,
OrdDate=o.OrderDate,
Amount=o.OrderAmount,
RunntingTotal =ord.Aggregate(0,(o a,o b)=>
{a.OrderAmount+b.OrderAmount;})
};

最佳答案

您不能使用内置的 Aggregate 方法执行此操作。

Darin's answer会给你你需要的东西,但有副作用(即,查询在枚举时更新 total 变量)。

如果您想要一个没有副作用的“纯”查询,那么您需要创建某种Accumulate 扩展方法并使用它代替Aggregate:

var query = ord.Accumulate(
new { Order = (OrderData)null, Total = 0.0 },
(a, x) => new { Order = x, Total = a.Total + x.OrderAmount });

foreach (var x in query)
{
Console.WriteLine("{0}\t{1}\t{2}\t{3}",
x.Order.OrderNumber, x.Order.OrderDate, x.Order.OrderAmount, x.Total);
}

// ...

public static class EnumerableExtensions
{
public static IEnumerable<TAccumulate> Accumulate<TSource, TAccumulate>(
this IEnumerable<TSource> source,
TAccumulate seed,
Func<TAccumulate, TSource, TAccumulate> func)
{
if (source == null)
throw new ArgumentNullException("source");

if (func == null)
throw new ArgumentNullException("func");

TAccumulate accumulator = seed;
foreach (TSource item in source)
{
accumulator = func(accumulator, item);
yield return accumulator;
}
}
}

关于c# - Linq 对列表使用 Aggregate(),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1873134/

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