python - 与 python 中每个确切位置的列表进行比较

Question

我有 2 个列表:

Gigits_List 和 Guesses_list。

我需要比较它们并找到哪里有公牛和奶牛(就像真正的游戏一样)

例如:如果一个列表是 ['1', '3', '4', '6'] 而第二个列表是 ['2', '3' ，'6'，'4']。所以是“2C 1B”2头牛和1头牛

    #setting the secret length
    Secret_Length = int(raw_input("the secret length"))

    #setting the secret base
    Secret_Base = int(raw_input("secret base_between 6-10"))

    #getting the secret from the user
    Secret = str(raw_input("enter the secret"))

    #checking if the secret in the right length
    if (int(len(Secret)) != Secret_Length):
        print "ERROR"
        sys.exit()

    Gigits_List = []
    #checking if the number in the right base
    for Each_Digigt in Secret:
        Gigits_List.append(Each_Digigt)
        if (int(Each_Digigt)>Secret_Base-1):
            print "ERROR"
            sys.exit

    #getting a guess from the user
    Guess = str(raw_input("enter the guess"))

    Guesses_list = []
    for Each_Guess in Guess:
        Guesses_list.append(Each_Guess)

Answer 1

list1 = ['1', '2', '3', '3']
list2 = ['1', '3', '3', '3']

cow, bull, removed = 0, 0, 0
for i in range(len(list1)):
    if list1[i - removed] == list2[i - removed]:
        bull += 1
        list1 = list1[:i - removed] + list1[i - removed + 1:]
        list2 = list2[:i - removed] + list2[i - removed + 1:]
        removed += 1
for i in range(len(list2)):
    if list2[i] in list1:
        cow += 1
print cow, bull

输出

0 3