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python - PyShp - 让 Python 识别折线中的点

转载 作者:太空宇宙 更新时间:2023-11-03 18:38:52 25 4
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我对 Python 相当陌生,所以我怀疑我遇到的这个问题是出于天真,但任何帮助将不胜感激。

目前我有一个小型的沿海演化模型。最初,使用 NumPy 在某些约束内沿着定义的 x 轴随机生成 100 个点。相关部分代码是这样的:

# assign the number of points along the beach       
Num_P_Coast = 100

# node spacing
dx = 10
x_vec = np.zeros(Num_P_Coast)

for i in range(0,Num_P_Coast):
x_vec[i] = dx*i

# initialize beach and cliff with random numbers
Bch_Width = np.random.uniform(0, 30, Num_P_Coast)
Cl_Loc = np.random.uniform(30, 60, Num_P_Coast)

然后模型使用这两条初始线进行模型计算。我试图做的是使用 PyShp 读取在 ArcMap 中绘制的折线来替换这些随机生成的点,然后将其用于模型计算。我正在尝试的代码是这样的:

BS1 = shp.Reader("Beach2.shp") #calling shapefile of beach front location
CL1 = shp.Reader("Cliff2.shp") #calling shapefile of cliff location

p1 = BS1.shapes()
b = p1[0]
BeachShp1 = b.points

p2 = CL1.shapes()
c = p2[0]
CliffShp1 = c.points

Bch_Width = np.random.uniform(0, 30, BS1) #Attempt to use polyline of beach to generate initial beach location
Cl_Loc = np.random.uniform(30, 60, CL1) #Attempt to use polyline of beach to generate initial beach location

当我尝试对代码进行微小更改时,这会不断出现“TypeError:需要整数”和“ValueError:序列太大;必须小于 32”等错误。

有谁知道需要做什么才能让代码接受折线上的点,而不是随机生成的点?我觉得它应该很简单,但我已经浏览了 PyShp 文档和其他问题,似乎找不到该怎么做。

干杯

完整代码:

def toy_beach_model(): #this is the main part of the program, which will call the     evol_equations function to do all the jiggery pokery of outputting beach evolution

#where do you want to put it
#OutputDirectory = str(raw_input("Enter output directory:"))
OutputDirectory = 'c:/python_results/graphs/'
OutputModelName = eg.enterbox(title = 'Model name', msg = 'Enter model ID:')
ModelDesc = eg.enterbox(title = 'Model description', msg = 'Enter short description of model' )

# assign the number of points along the beach
Num_P_Coast = 100

# node spacing
dx = 10
x_vec = np.zeros(Num_P_Coast)

# some parameters
Cl_Eros_NoBch = int(eg.enterbox(title = 'Erosion rate', msg = 'Enter erosion rate:'))


Cl_Eros_HRock = Cl_Eros_NoBch * 0.5 #simulating harder rock = headland evolution

Cl_Eros_Efold = 50

Sup_Rate = int(eg.enterbox(title = 'Sediment supply', msg = 'Enter sediment supply rate:'))
K = 0.5


# set up x vector
for i in range(0,Num_P_Coast):
x_vec[i] = dx*i

BS1 = shp.Reader("Beach2.shp") #calling shapefile of beach front location
CL1 = shp.Reader("Cliff2.shp") #calling shapefile of cliff location

p1 = BS1.shapes()
b = p1[0]
BeachShp1 = b.points

p2 = CL1.shapes()
c = p2[0]
CliffShp1 = c.points


# initialize beach and cliff with random numbers
#Bch_Width = np.random.uniform(0, 30, Num_P_Coast)
#Cl_Loc = np.random.uniform(30, 60, Num_P_Coast)

Bch_Width = np.random.uniform(0, 30, BeachShp1) #Attempt to use polyline of beach to generate initial beach location
Cl_Loc = np.random.uniform(30, 60, CliffShp1) #Attempt to use polyline of beach to generate initial beach location


#H_Loc = Cl_Loc
#H_Loc = np.random.uniform(0, 8, Num_P_Coast)
H_Loc = np.random.random_sample(Num_P_Coast)
BcH_Eros = Bch_Width+Cl_Loc

# lets have this evolve through time

# time spacing in years
dt = 10

# number of time steps
n_timesteps = int(eg.enterbox(title = 'Timestep', msg = 'Enter number of iterations'))

# set up the beach erosion vector
Cl_Eros = np.zeros(Num_P_Coast)

H_Eros = np.zeros(Num_P_Coast)

# initial headland erosion
H_Eros = dt*Cl_Eros_HRock*np.exp(-Bch_Width/Cl_Eros_Efold)

# initial erosion
Cl_Eros = dt*Cl_Eros_NoBch*np.exp(-Bch_Width/Cl_Eros_Efold)

最佳答案

该错误是因为您正在尝试使用 Bch_Width = np.random.uniform(0, 30, BeachShp1) 等创建一个(可能)几千维数组。

numpy.random.uniform 期望生成的数组的低值、高值和形状。

例如:

In [1]: import numpy as np

In [2]: np.random.uniform(0, 5) # Generate a single random number between 0 and 5
Out[2]: 4.149771995503083

In [3]: np.random.uniform(0, 5, 3) # Generate an array of three numbers
Out[3]: array([ 2.25725653, 0.70070352, 0.62541689])

In [4]: np.random.uniform(0, 5, (2,2)) # Generate a 2x2 array of 4 numbers
Out[4]:
array([[ 0.89355128, 3.30796407],
[ 1.23816971, 1.12224456]])

当你运行时:

p1 = BS1.shapes()
b = p1[0]
BeachShp1 = b.points

BeachShp1 是 x,y 坐标序列。基本上,您正在尝试执行以下操作:

np.random.uniform(low, high, [[19.554, 45.998], [20.889, 24.009], ... ])

...这没有任何意义。

您是否正在尝试向 shapefile 表示的线添加随机海滩宽度?或者计算悬崖轮廓与海滩轮廓之间的距离?或者完全是别的什么?

关于python - PyShp - 让 Python 识别折线中的点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20999758/

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