Ruby 正则表达式匹配字符串前面有数字范围

Question

我有 2 个字符串:

I have 4 cars in my house
I have 14 cars in my house

我们如何使用 ruby​​ (1.9.3) 正则表达式来检查只有 1 到 10 辆汽车匹配？

例如:

I have 1 car in my house # => match
I have 4 cars in my house # => match
I have 10 cars in my house # => match
I have 14 cars in my house # => should not match
I have 100 cars in my house # => should not match

此外，我们如何匹配(即 2 辆汽车)与任何字符串？因此，如果目标字符串包含“22 辆汽车”，则它不应匹配。

例如:

some other string before 2 cars some other string after # => match
some other string before 22 cars some other string after # => should not match    

Answer 1

使用这个正则表达式:/I have ([1-9]|10) cars?在我家。/

[1-9] 创建范围 1,2,3,4,5,6,7,8,9 并且竖线字符作为 or 允许 10。括号是捕获组。 cars 末尾的“s”后面的问号表示“零个或一个前面的字符”，因此与“car”和“cars”都匹配。希望这对您有所帮助!