python - 连接4水平胜利检查错误

Question

几天来我一直在尝试解决这个问题...这是代码...

def checkhor(array):
    for x in range(1, 8):
        if (array[x] == "#") or (array[x] == "@") and (array[x] <= 4):
            if (array[x] == array[(x + 1)]) and (array[x] == array[(x + 2)]) and (array[x] == array[(x + 3)]):
                if turn == 0:
                    print "You Won!"
                    return True
                else:
                    print "You Lost..."
                    return True

...这是错误

File "/home/firearrow5235/PycharmProjects/Connect 4/Connect 4.py", line 132, in <module>
if checkhor(f):
  File "/home/firearrow5235/PycharmProjects/Connect 4/Connect 4.py", line 77, in checkhor
if (array[x] == array[(x + 1)]) and (array[x] == array[(x + 2)]) and (array[x] == array[(x + 3)]):
IndexError: list index out of range

重点是，这个错误弹出的次数确实是零星的……我可以跑几轮将棋子放置在七个插槽中的任何一个中都没有问题...我将把我最后的输入放入...

['A', '#', 'O', 'O', 'O', 'O', 'O', 'O']
['B', '@', 'O', 'O', 'O', 'O', 'O', 'O']
['C', '@', 'O', 'O', 'O', 'O', 'O', 'O']
['D', '#', 'O', 'O', 'O', 'O', 'O', 'O']
['E', '@', '@', 'O', 'O', 'O', 'O', 'O']
['F', '@', '#', '#', 'O', '#', '#', 'O']
[' ', '1', '2', '3', '4', '5', '6', '7']
Enter the column you'd like to drop your piece in4

我还会添加一 block 板，表明问题不在于该部分的位置

Enter the column you'd like to drop your piece in5
['A', 'O', 'O', 'O', 'O', 'O', 'O', 'O']
['B', 'O', 'O', 'O', 'O', 'O', 'O', 'O']
['C', 'O', 'O', 'O', 'O', 'O', 'O', 'O']
['D', 'O', 'O', 'O', 'O', 'O', 'O', 'O']
['E', 'O', 'O', 'O', 'O', 'O', 'O', 'O']
['F', 'O', 'O', 'O', 'O', '@', 'O', 'O']
[' ', '1', '2', '3', '4', '5', '6', '7']

Answer 1

我相信这与您的条件有关:

if (array[x] == "#") or (array[x] == "@") and (array[x] <= 4):

如果我正确理解你的代码，最后的检查应该是确保你没有超出 x >= 4 的范围。 ，但你有array[x] >= 4相反。

此外，您可能需要在 or 周围添加一些额外的括号。 :

>>> True or False and False
True
>>> (True or False) and False
False

其中任何一个都可能有助于通过条件，然后得到你的 IndexError当您尝试索引 x+3 时