Python:For循环仅循环txt文件的第一部分

Question

最近我必须为实习编写一个脚本来检查子网是否出现在一堆路由器/交换机配置中。

我制作了一个生成输出的脚本。现在我需要第二个脚本(我无法让它工作到一个)，它读取输出，如果子网出现，则将其写入 aanwezig.txt，如果没有写入 nietAanwezig .txt.

很多其他答案帮助我制作了这个脚本，它可以工作，但它只针对前 48 个 IP 执行，并且有超过 2000 个......

checkOutput.py的代码:

def main():

    file = open('../iprangesclean.txt', 'rb')
    aanwezig = open('../aanwezig.txt', 'w')
    nietAanwezig = open('../nietAanwezig.txt', 'w')
    output = open('output.txt', 'rb')

    for line in file:
        originalLine = line
        line.rstrip()
        line = line.replace(' ', '')
        line = line.replace('\n', '')
        line = line.replace('\r', '')
        one,two,three,four = line.split('.')

        # 3Byte IP:
        ipaddr = str(one) + "." + str(two) + "." + str(three)

        counter = 1
        found = 0   
        for lijn in output:

            if re.search("\b{0}\b".format(ipaddr),lijn) and found == 0:
                found = 1                               
            else:
                found = 2

            print counter
            counter= counter + 1

        if found == 1:
            aanwezig.write(originalLine)
            print "Written to aanwezig"
        elif found == 2:
            nietAanwezig.write(originalLine)
            print "Written to nietAanwezig"
        found = 0

    file.close()
    aanwezig.close()
    nietAanwezig.close()


main()

iprangesclean.txt的格式如下:

10.35.6.0/24
10.132.42.0/24
10.143.26.0/24
10.143.30.0/24
10.143.31.0/24
10.143.32.0/24
10.35.7.0/24
10.143.35.0/24
10.143.44.0/24
10.143.96.0/24
10.142.224.0/24
10.142.185.0/24
10.142.32.0/24
10.142.208.0/24
10.142.70.0/24
and so on...

output.txt 的一部分(我无法为您提供所有内容，因为它包含用户信息):

*name of device*.txt:logging 10.138.200.100
*name of device*.txt:access-list 37 permit 10.138.200.96 0.0.0.31
*name of device*.txt:access-list 38 permit 10.138.200.100
*name of device*.txt:snmp-server host 10.138.200.100 *someword*
*name of device*.txt:logging 10.138.200.100

Answer 1

尝试这个改变:

for lijn in output:
    found = 0 # put this here
    if re.search("\b{0}\b".format(ipaddr),lijn) and found == 0:
        found = 1
    else:
        found = 2

    print counter
    counter= counter + 1

    """Indent one level so it us in the for statement"""
    if found == 1:
        aanwezig.write(originalLine)
        print "Written to aanwezig"
    elif found == 2:
        nietAanwezig.write(originalLine)
        print "Written to nietAanwezig"

如果我正确理解了这个问题，这应该会引导您走向正确的方向。 if 语句 当前未在for 语句 中执行。如果这确实解决了您的问题，那么您也不需要 found 变量。你可以有这样的东西:

for counter, lijn in enumerate(output, 1):
    if re.search("\b{0}\b".format(ipaddr),lijn):
        aanwezig.write(originalLine)
        print "Written to aanwezig"
    else:
        nietAanwezig.write(originalLine)
        print "Written to nietAanwezig"

    print counter

如果我误解了这个问题，请告诉我。

注意我尚未测试上面的代码，请尝试将它们作为起点。