python - 如何在 Django Admin 中按多种自定义方法排序

Question

我希望能够在 Django Admin 中按几种自定义方法进行排序。 This question仅提供一种方法的解决方案。

我尝试修改它:

from django.db import models

class CustomerAdmin(admin.ModelAdmin):
    list_display = ('number_of_orders','number_of_somevalue') # added field

    def queryset(self, request):
        qs = super(CustomerAdmin, self).queryset(request)
        qs = qs.annotate(models.Count('order'))
        qs = qs.annotate(models.Count('somevalue')) # added line
        return qs

    def number_of_orders(self, obj):
        return obj.order__count
    number_of_orders.admin_order_field = 'order__count'

    def number_of_somevalue(self, obj): # added method
        return obj.somevalue__count
    number_of_somevalue.admin_order_field = 'somevalue__count'

并且它工作不正确。看起来它是将 count 值相乘，而不是单独计算它们。

示例:

我有 2 个订单和 2 个某些值，但在面板中我看到 4 个订单和 4 个某些值。

添加另一个具有另一个值的方法使其变为 8 (2*2*2)。

如何修复它？

Answer 1

您可以尝试按多种自定义方法进行排序(已测试):

from django.db.models import Count

class CustomerAdmin(admin.ModelAdmin):

    # The list display must contain the functions that calculate values
    list_display = ('number_of_orders','number_of_somevalue') # added field

    # Overwrite queryset in model admin
    def queryset(self, request):
        qs = super(CustomerAdmin, self).queryset(request)
        # The query have to return multiple annotation, for this use distinct=True in the Count function
        qs = qs.annotate(number_orders = Count('order', distinct=True)).annotate(number_somevalue = Count('somevalue',distinct=True)) 
        return qs

    # This function return the new field calculated in queryset (number_orders)
    def number_of_orders(self, obj):
        return obj.number_orders

    number_of_orders.admin_order_field = 'numberorders' # sortable new column

    # And this one will return the another field calculated (number_somevalue)
    def number_of_somevalue(self, obj): # added method
        return obj.number_somevalue

    number_of_somevalue.admin_order_field = 'number_somevalue'# sortable new column