python - 装饰器将实例方法转换为类函数

Question

我需要传递几个方法作为回调，这些方法不采用 self争论。这就是我当前的代码的样子:

def _do_callback(callback, log, *args):
    try:
        # some common code
        callback(*args)
    except:
        log.error('XX')

class Foo(object):
    def __init__(self):
        self.log = Log('Foo')
        self.cb1_wrapper = lambda x: _do_callback(self.cb1, self.log, x)  # I need a function taking one parameter
        self.cb2_wrapper = lambda x: _do_callback(self.cb2, self.log, x)

    def cb1(self, x):
        # some code accessing self

    def cb2(self, x):
        # some code accessing self

    def register_callbacks(self):
        register('1', self.cb1_wrapper)
        register('2', self.cb2_wrapper)

是否可以编写一些装饰器来应用于 cb1和cb2能够将结果传递到当前需要 self.cb1_wrapper 的代码中？

(我知道标题不理想，请随意编辑)

Answer 1

当然；想想未包装的方法应该是什么样子:

def callback(fn):
    def inner(self, *args):
        return _do_callback(fn.__get__(self, type(self)), self.log, *args)
    return inner

class Foo(object):
    def __init__(self):
        self.log = Log('Foo')

    @callback
    def cb1_wrapped(self, x):
        pass