Python ctypes : get handle to already-loaded shared libraries

Question

给定共享库的短名称(例如 gomp，而不是 libgomp.so 等)，Python 中确定该库是否已加载的最佳方法是什么，如果是，则找到其完整路径名，以便 ctypes 句柄可以可以得到吗？

Answer 1

这是迄今为止我能想到的最好的解决方案，但从/proc/<pid>/maps阅读感觉有点老套。并对其内容进行字符串解析。

import re, ctypes, os.path

_WHITESPACE = re.compile('\s+')

def get_loaded_lib_pathname(lib_name):
    soname = 'lib%s.so' % (lib_name,)
    pid = os.getpid()
    with open('/proc/%d/maps' % (pid,)) as f:
        for line in f.readlines():
            tokens = _WHITESPACE.split(line)
            addrs, perms, offset, dev, inode, pathname = tokens[:6]
            basename = os.path.basename(pathname)
            if basename.startswith(soname):
                return pathname
    return None

def get_lib_handle(lib_name):
    pathname = get_loaded_lib_pathname(lib_name)
    if pathname is None:
        return None
    return ctypes.cdll.LoadLibrary(pathname)

libgomp = get_lib_handle('gomp')