ruby-on-rails - 如何根据 Controller 名称查询模型

Question

我一直在重构我的模型和 Controller ，以努力消除代码重复，到目前为止，它似乎都是桃子般的奶油状。目前我有一些我的两个 Controller 通用的代码，如下所示:

def process_filters
# Filter hash we're going to pass to the model
  filter_to_use = {}

  # To process filters, we first query the model to find out what filters
  # we should be looking for, as the model knows what we can filter.
  Iso.available_filters.each do |filter|
    # We should have our array with our filter listing.
    # Check the purchase order model for a description
    filter_name = filter[0][:filter_name]

    # Filters are stored in a session variable, this way filters survive
    # page reloads, etc.  First thing we do, is set the session if new filters
    # have been set for the filter.
    session_name = session_filter_name( filter_name )
    if params[session_name]
      if params[session_name] == 'All'
        session[session_name] = nil
      else
        session[session_name] = params[session_name]
        filter_to_use[filter_name] = params[session_name]
      end
    elsif session[session_name]
      # If params aren't read, we still need to filter based off the users
      # session
      filter_to_use[filter_name] = session[session_name]
    end
  end

  # Just using this variable for now until I can refactor the helper code
  # so that this is passed in.
  @current_filter_values = filter_to_use

  filter_to_use[:page] = @current_page

  @isos = Iso.find_filtered( filter_to_use )

  if @isos.out_of_bounds?
    filter_to_use[:page] = session[:previous_page] = @current_page = 1
    @isos = Iso.find_filtered( filter_to_use )
  end
end

现在这段代码与另一个 Controller 中的代码完全相同，除了模型引用(在本例中为 Iso)。有什么办法可以使该模型引用动态化吗？

基本上，我想将 Iso 引用(包括 @iso 变量)替换为基于 controller.controller_name 或类似内容的内容。

Answer 1

您可以将此代码移动到模块中，将此模块混合到您需要的所有 Controller 中，并使用模块内的 self.class 变量来确定具体的 Controller 名称。使用此名称，您可以使用标准字符串函数(例如大写)和 Kernel.const_get 函数通过名称获取类。