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python - Python 中的快速组合生成器

转载 作者:太空宇宙 更新时间:2023-11-03 17:58:39 25 4
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作为 python 大型项目的一部分,我需要一个快速生成器函数,它生成所有可能的小于 n 的非负整数集合,使得每个集合最多有 s 个元素,并且集合中最大和最小数字之间的差值小于 w

到目前为止,我实现的最快实现是使用 itertools:

import itertools

def subsample(n, s, w):
nn = range(w)
for p in range(s):
o = list(itertools.combinations(nn, p+1))
for t in o:
yield t
for _ in range(0, n-w):
pt = o
o = [tuple([op + 1 for op in list(u)]) for u in pt]
for t in list((set(o) ^ set(pt)) & set(o)):
yield t

例如:

In [1]: list(subsample(6,3,3))
Out [1]: [(0,), (1,), (2,), (3,), (4,), (5,), (0, 1), (0, 2), (1, 2), (1, 3), (2, 3), (3, 4), (2, 4), (4, 5), (3, 5), (0, 1, 2), (1, 2, 3), (2, 3, 4), (3, 4, 5)]

但我坚信必须有更有效的方法来做到这一点。有什么办法可以让它更快吗?

最佳答案

以下是一些基于 Knuth 算法的生成器。

  • subsets4 生成具有 k 或更少元素的 1..n 的所有子集
  • subsets5subsets4 生成的子集限制为最大差异为 w
  • subsets 生成 1..n 的所有子集,长度恰好为 k
  • subsets2subsets 生成的子集限制为最大差异为 w

运行 megatest() 函数来测试 subsets5 生成器的多个值 nkw

# all subsets of k or less elements of 1..n
def subsets4(n,k):
a = [ 0 ] * k
i = 0
while i >= 0:
a[i] += 1
yield a[0:i+1]
r = a[i]+1
i += 1
while i < k and r <= n:
a[i] = r
yield a[0:i+1]
i += 1
r += 1
i -= 1
if a[i] >= n:
i -= 1

# all subsets of k or less elements of 1..n with max difference <= w
def subsets5(n,k,w):
a = [ 0 ] * k
i = 0
while i >= 0:
a[i] += 1
yield a[0:i+1]
r = a[i]+1
i += 1
while i < k and r <= n and r-a[0] <= w:
a[i] = r
yield a[0:i+1]
i += 1
r += 1
i -= 1
if a[i] >= n or a[i]+1-a[0] > w:
i -= 1

# all subsets of 1..n having exactly k elements
def subsets(n,k):
a = range(1,k+1)
while a[0] <= n+1-k:
yield a
# find i
i = k-1
while i >= 0 and a[i]+k-i >= n+1: i -= 1
r = a[i]
a[i] += 1
j = 2
i += 1
while i < k:
a[i] = r + j
i += 1
j += 1

# all subsets of 1..n having exactly k elements and whose max
# difference is w
def subsets2(n,k,w):
if k > w: return
a = range(1,k+1)
while a[0] <= n+1-k:
yield a
i = k-1
while i >= 0 and (a[i]+k-i >= n+1 or a[i]+k-i-a[0] > w) : i -= 1
r = a[i]
a[i] += 1
j = 2
i += 1
while i < k:
a[i] = r + j
i += 1
j += 1

def test(n,k,w):
s1 = [ s for s in subsets4(n,k) if s[-1] - s[0] <= w ]
s2 = [ s for s in subsets5(n,k,w) ]
if s1 == s2:
print "OK", n,k,w
return 0
else:
print "NOT OK", n, k, w
return 1

# for s in subsets2(10,3,4): print s
# for s in subsets(10,3): print s
def megatest():
failed = 0
for n in xrange(10,20):
for k in xrange(1,n+1):
for w in xrange(k,n+1):
failed += test(n,k,w)
print "failed:", failed

关于python - Python 中的快速组合生成器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28079416/

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