c# - c#中的密码生成器

Question

我想在我的 ASP.NET C# Web 应用程序中创建一个随 secret 码生成器。

我已经创建了它，但它仅适用于整数格式。如果我给出任何字符，它会将调试错误显示为“我的输入格式错误”。

但我想同时输入字符串和整数。例如我的文本框字段可能是

dft-001

我想要这个值的随 secret 码，而且我的长度应该限制为 8 位数字或字符。

我当前的代码:

public static string CreateRandomPassword(int PasswordLength)
    {

        string _allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789-";
        Random randNum = new Random();
        char[] chars = new char[PasswordLength];
        int allowedCharCount = _allowedChars.Length;

        for (int i = 0; i < PasswordLength; i++)
        {
            chars[i] = _allowedChars[(int)((_allowedChars.Length) * randNum.NextDouble())];
        }

        return new string(chars);
    }


protected void Button1_Click(object sender, EventArgs e)
    {
        userid.Text = "Your id is:     " + id.Text;
        if(id .Text!="")
        {

            string myInt = id.Text.ToString(); 
            password.Text = "Your password is: " + CreateRandomPassword(int.Parse(myInt)); 
        }
       }

Answer 1

根据您在要求中所述的内容，您可以采取一些措施来纠正此问题。

public static string CreateRandomPassword()  //If you are always going to want 8 characters then there is no need to pass a length argument
    {
        string _allowedChars = "abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNOPQRSTUVWXYZ0123456789-";
        Random randNum = new Random((int)DateTime.Now.Ticks);  //Don't forget to seed your random, or else it won't really be random
        char[] chars = new char[8];
        //again, no need to pass this a variable if you always want 8

        for (int i = 0; i < 8; i++)
        {
            chars[i] = _allowedChars[randNum.Next(_allowedChars.Length)];
            //No need to over complicate this, passing an integer value to Random.Next will "Return a nonnegative random number less than the specified maximum."
        }
        return new string(chars);
    }


protected void Button1_Click(object sender, EventArgs e)
    {
        userid.Text = "Your id is:     " + id.Text;
        if(id .Text!="")
        {
            password.Text = "Your password is: " + CreateRandomPassword(); 
        }
    }

如果我已经理解您想要正确执行的操作，那么这应该可以帮助您。

引用: MSDN Random.Next