python - 列表列表，我似乎无法正确缩进

Question

现在没有缩进错误了:

def best_wild_hand(hand):
  #Try all values for jokers in all 5-card selections.
  blackJoker= "?B"
  redJoker = "?R"


  dictSuit = {'2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9, 'T':10, 'J':11, 'Q':12, 'K':13, 'A':14 }
  listofLists = []

  if blackJoker in hand:

    newHand = hand.remove(blackJoker)
    for d in dictSuit:
      listofLists.append(newHand.append(d + "S"))
    return listofLists

我正在尝试获取一个列表列表，其中是否在传递给 best_wild_hand 方法的手形参数列表中找到 blackJoker。如果发现黑手，我们将其移除并将 2..13 + C(牌组中发现的所有三叶草牌)附加到手上。我正在尝试制作一个包含 1 个三叶草的手牌列表(因此手牌列表 + nC)n 为数字 2- 13

我的预期输出是列表列表，每个列表中都有 2C...13C，它取代了黑色扑克

没有更多错误，但是当我在此打印语句中运行时，代码不会返回任何错误

print best_wild_hand(['6C', '7C', '8C', '9C', 'TC', '5C', '?B'])  

Answer 1

进行编辑以匹配您的编辑

您的问题是您正在将变量分配给方法。这导致变量为 None:

>>> y = ['6C'].remove('6C')
>>> print y
None
>>> 

相反，改变

newHand = hand.remove(blackJoker)

至

newHand = hand
newHand.remove(blackJoker)

因此:

def best_wild_hand(hand):
  #Try all values for jokers in all 5-card selections.
  blackJoker= "?B"
  redJoker = "?R"


  dictSuit = {'2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9, 'T':10, 'J':11, 'Q':12, 'K':13, 'A':14 }
  listofLists = []

  if blackJoker in hand:

    newHand = hand
    newHand.remove(blackJoker)
    for d in dictSuit:
      listofLists.append(newHand.append(d + "S"))
    return listofLists

现在当我运行你的代码时:

bash-3.2$ python safd.py
[None, None, None, None, None, None, None, None, None, None, None, None, None]
bash-3.2$ 

^{也许不是您想要的，但它仍然在打印}