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python - 无法在 OSX 上成功执行 ipython 笔记本命令

转载 作者:太空宇宙 更新时间:2023-11-03 17:52:26 25 4
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我安装了 Anaconda python 发行版。但是,执行“ipython Notebook”后,我无法成功执行它,并且系统产生以下错误。我一头雾水,到底出了什么问题?

谢谢。

AbhayBhadani-MacBook:~ abhaybhadani$ ipython --version

3.0.0

AbhayBhadani-MacBook:~ abhaybhadani$ which ipython

/opt/anaconda/bin/ipython

AbhayBhadani-MacBook:~ abhaybhadani$ ipython notebook

[I 11:25:33.829 NotebookApp] Using existing profile dir: u'/Users/abhaybhadani/.ipython/profile_default'

[I 11:25:33.833 NotebookApp] Using MathJax from CDN: https://cdn.mathjax.org/mathjax/latest/MathJax.js
Traceback (most recent call last):

File "/opt/anaconda/bin/ipython", line 11, in <module>
sys.exit(start_ipython())

File "/opt/anaconda/lib/python2.7/site-packages/IPython/__init__.py", line 120, in start_ipython
return launch_new_instance(argv=argv, **kwargs)

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 573, in launch_instance
app.initialize(argv)

File "<string>", line 2, in initialize

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
return method(app, *args, **kwargs)

File "/opt/anaconda/lib/python2.7/site-packages/IPython/terminal/ipapp.py", line 321, in initialize
super(TerminalIPythonApp, self).initialize(argv)

File "<string>", line 2, in initialize

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
return method(app, *args, **kwargs)

File "/opt/anaconda/lib/python2.7/site-packages/IPython/core/application.py", line 369, in initialize
self.parse_command_line(argv)

File "/opt/anaconda/lib/python2.7/site-packages/IPython/terminal/ipapp.py", line 316, in parse_command_line
return super(TerminalIPythonApp, self).parse_command_line(argv)

File "<string>", line 2, in parse_command_line

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
return method(app, *args, **kwargs)

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 471, in parse_command_line
return self.initialize_subcommand(subc, subargv)

File "<string>", line 2, in initialize_subcommand

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
return method(app, *args, **kwargs)

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 409, in initialize_subcommand
self.subapp.initialize(argv)

File "<string>", line 2, in initialize

File "/opt/anaconda/lib/python2.7/site-packages/IPython/config/application.py", line 75, in catch_config_error
return method(app, *args, **kwargs)

File "/opt/anaconda/lib/python2.7/site-packages/IPython/html/notebookapp.py", line 980, in initialize
self.init_webapp()

File "/opt/anaconda/lib/python2.7/site-packages/IPython/html/notebookapp.py", line 842, in init_webapp
self.http_server.listen(port, self.ip)

File "/opt/anaconda/lib/python2.7/site-packages/tornado/tcpserver.py", line 125, in listen
sockets = bind_sockets(port, address=address)

File "/opt/anaconda/lib/python2.7/site-packages/tornado/netutil.py", line 145, in bind_sockets
sock.bind(sockaddr)

File "/opt/anaconda/lib/python2.7/socket.py", line 224, in meth
return getattr(self._sock,name)(*args)

error: [Errno 49] Can't assign requested address


If you suspect this is an IPython bug, please report it at:
https://github.com/ipython/ipython/issues
or send an email to the mailing list at ipython-dev@scipy.org


You can print a more detailed traceback right now with "%tb", or use "%debug"
to interactively debug it.


Extra-detailed tracebacks for bug-reporting purposes can be enabled via:
c.Application.verbose_crash=True

最佳答案

这只是建立在 @Abhay Bhadani 已经为自己提供的答案的基础上,因为我自己似乎找不到根本原因

您可以尝试编辑您的 ipython 配置文件。就我而言,我必须使用以下命令创建配置文件:

ipython profile create

然后将以下行附加到 ipython 笔记本配置中。在我的例子中,该文件位于 ~/.ipython/profile_default/ipython_notebook_config.py ,这是在没有名称的情况下创建的配置文件的默认位置。找到后,附加以下配置选项:

c.NotebookApp.ip = '127.0.0.1'

然后,当运行ipython Notebook时,它将照常打开,无需提供 ip 参数。所以你的解决方案并没有太大的改进,但我更喜欢这样:)

如果您确实想知道在配置或命令行中未提供 IP 时为什么或调用什么地址,您可以在同一内容中附加以下内容配置文件:

c.Application.verbose_crash=True

就我而言,运行ipython笔记本会给出以下输出:

--> 228     return getattr(self._sock,name)(*args)
global getattr = undefined
self._sock = <socket object, fd=6, family=2, type=1, protocol=6>
name = 'bind'
args = (('192.168.77.104', 8888),)
229
230 for _m in _socketmethods:
231 p = partial(meth,_m)
232 p.__name__ = _m
233 p.__doc__ = getattr(_realsocket,_m).__doc__
234 m = MethodType(p,None,_socketobject)
235 setattr(_socketobject,_m,m)
236
237 socket = SocketType = _socketobject
238
239 class _fileobject(object):
240 """Faux file object attached to a socket object."""
241
242 default_bufsize = 8192
243 name = "<socket>"

error: [Errno 49] Can't assign requested address

这只是给了我一个提示,表明它可能正在尝试访问无效的 IP。

关于python - 无法在 OSX 上成功执行 ipython 笔记本命令,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28936095/

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