python - Scrapy从第一个元素和帖子标题收集数据

Question

我需要 Scrapy 从此标签收集数据并检索所有三个部分。输出将类似于:

Tonka double shock boys bike - $10 (Denver).

<span class="postingtitletext">Tonka double shock boys bike - <span class="price">$10</span><small> (Denver)</small></span>

第二个是从第一个跨度标签收集数据。所以结果只会是:

2016 2004 Pontiac Grand Prix gt.

 <p class="attrgroup"><span><b>2016 2004 Pontiac Grand Prix gt</b></span> <span>odometer: <b>164</b></span>  <span>fuel : <b>gas</b></span> <span>transmission : <b>automatic</b></span> <span>title status : <b>clean</b></span></p>

这是迄今为止我的代码:

   # -*- coding: utf-8 -*-
# scrapy crawl dmoz -o items.csv -t csv
import re
import scrapy
from scrapy.http import Request


# item class included here
class DmozItem(scrapy.Item):
    # define the fields for your item here like:
    link = scrapy.Field()
    attr = scrapy.Field()
    title = scrapy.Field()
    tag = scrapy.Field()

class DmozSpider(scrapy.Spider):
    name = "dmoz"
    allowed_domains = ["craigslist.org"]
    start_urls = [
    "http://jxn.craigslist.org/search/cto?"
    ]

    BASE_URL = 'http://jxn.craigslist.org/'

    def parse(self, response):
        links = response.xpath('//a[@class="hdrlnk"]/@href').extract()
        for link in links:
            absolute_url = self.BASE_URL + link
            yield scrapy.Request(absolute_url, callback=self.parse_attr)

    def parse_attr(self, response):
        match = re.search(r"(\w+)\.html", response.url)
        if match:
            item_id = match.group(1)
            url = self.BASE_URL + "reply/nos/vgm/" + item_id

            item = DmozItem()
            item["link"] = response.url
            item["title"] = "".join(response.xpath("//span[@class='postingtitletext']//text()").extract())
            item["tag"]=response.xpath("//p[@class='attrgroup']/span/b/text()").extract()
            return scrapy.Request(url, meta={'item': item}, callback=self.parse_contact)

    def parse_contact(self, response):
        item = response.meta['item']
        item["attr"] = "".join(response.xpath("//div[@class='anonemail']//text()").extract())
        return item

Answer 1

要发布标题，请从 span 标记中获取所有文本节点并将它们连接起来:

$ scrapy shell http://denver.craigslist.org/bik/5042090428.html
In [1]: "".join(response.xpath("//span[@class='postingtitletext']//text()").extract())
Out[1]: u'Tonka double shock boys bike - $10 (Denver)'

请注意，执行此操作的“Scrapy-way”是使用 ItemLoader和 Join()处理器。

<小时/>

Second is to collect data from first span tag.

由于您尚未提供示例输入数据，因此这是一个有根据的猜测:

response.xpath("//p[@class='attrgroup']/span/b/text()").extract()[0]