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python - DBSCAN 返回部分簇

转载 作者:太空宇宙 更新时间:2023-11-03 17:40:51 26 4
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我正在尝试在这里实现 DBSCAN 的代码:http://en.wikipedia.org/wiki/DBSCAN

我感到困惑的部分是

expandCluster(P, NeighborPts, C, eps, MinPts)
将 P 添加到集群 C
对于 NeighborPts 中的每个点 P'
如果 P' 没有被访问过
将 P' 标记为已访问
NeighborPts' = 区域查询(P', eps)
如果 sizeof(NeighborPts') >= MinPts
NeighborPts = NeighborPts 与 NeighborPts' 相连
如果 P' 还不是任何集群的成员
将P'添加到集群C

我的代码如下。照原样,它当前返回部分簇,其中一个点应该是密度连接的,即使它不在紧邻 eps 邻域中。我的代码仅返回每个点的前几个邻居。

import numpy 
import time
from math import radians, cos, sin, asin, sqrt
import re, math


def haversine(lon1, lat1, lon2, lat2):
"""
Calculate the great circle distance between two points
on the earth (specified in decimal degrees) returned as kilometers
"""
# convert decimal degrees to radians
lon1, lat1, lon2, lat2 = map(radians, [lon1, lat1, lon2, lat2])
# haversine formula
dlon = lon2 - lon1
dlat = lat2 - lat1
a = sin(dlat/2)**2 + cos(lat1) * cos(lat2) * sin(dlon/2)**2
c = 2 * asin(sqrt(a))
km = 6367 * c
return km



def ST_DBSCAN(points,max_distance,MinPts):
global visited
visited = []
noise = []
cluster_id = 0
clusters = []
in_cluster = []
for p in points:
if p not in visited:
# neighbor_points = []
visited.append(p)
NeighborPts = regionQuery(p,points,max_distance)
if len(NeighborPts) < MinPts:
noise.append(p)
else:
cluster_id = cluster_id + 1
g = expandCluster(p,NeighborPts,max_distance,MinPts,in_cluster)
clusters.append(g)
return clusters

#return len(NeighborPts)

def expandCluster(p,NeighborPts,max_distance,MinPts,in_cluster):
in_cluster.append(p[0])
cluster = []
cluster.append(p[0])
for point in NeighborPts:
if point not in visited:
visited.append(point)
new_neighbors = regionQuery(point,points,max_distance)
if len(new_neighbors) >= MinPts:
new_neighbors.append(NeighborPts)
if point[0] not in in_cluster:
in_cluster.append(point[0])
cluster.append(point[0])
return cluster




def regionQuery(p,points,max_distance):
neighbor_points = []
for j in points:
if j != p:
# print 'P is %s and j is %s' % (p[0],j[0])
dist = haversine(p[1],p[2],j[1],j[2])
if dist <= max_distance:
neighbor_points.append(j)
neighbor_points.append(p)
return neighbor_points

我有下面的一个子集。点 1 和点 5 应相距 10.76 公里,因此它们不应出现在初始查询中,但它们应包含在同一簇中,因为点 5 通过点 3 进行密度连接。

pointList = [[1,36.4686,2.8289], 
[2,36.4706,2.8589],
[3,36.4726,2.8889],
[4,36.4746,2.9189],
[5,36.4766,2.9489],
[6,36.4786,2.9789],
[7,36.4806,3.0089],
[8,36.4826,3.0389],
[9,36.4846,3.0689],
[10,36.4866,3.0989]]

points= pointList

g = ST_DBSCAN(points,10,3)

最佳答案

您的 expandCluster 函数忘记了新的邻居。

您的设置更新已交换。

关于python - DBSCAN 返回部分簇,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30578298/

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