ruby 字符串拆分问题

Question

我有这个字符串:"asdasda=asdaskdmasd&asmda=asdasmda&ACK=成功&asdmas=asdakmsd&asmda=adasda"

我想获取ACK和&符号之间的值，ACK和&符号之间的值可以改变...

谢谢

我想要 ruby​​ 的解决方案。

Answer 1

require "cgi"

query_string = "asdasda=asdaskdmasd&asmda=asdasmda&ACK=Success&asmda=asdakmsd"
parsed_query_string = CGI.parse(query_string)
#=> { "asdasda" => ["asdaskdmasd"],
#     "asmda" => ["asdasmda", "asdakmsd"],
#     "ACK" => ["Success"] }

parsed_query_string["ACK"].first
#=> "Success"

如果您还想重建查询字符串(尤其是与 URL 的其余部分一起)，我建议您查看 addressable gem 。

require "addressable/uri"

# Note the leading '?'
query_string = "?asdasda=asdaskdmasd&asmda=asdasmda&ACK=Success&asmda=asdakmsd"
parsed_uri = Addressable::URI.parse(query_string)
parsed_uri.query_values["ACK"]
#=> "Success"

parsed_uri.query_values = parsed_uri.query_values.merge("ACK" => "Changed")
parsed_uri.to_s
#=> "?ACK=Changed&asdasda=asdaskdmasd&asmda=asdakmsd"
# Note how the order has changed and the duplicate key has been removed due to
# Addressable's built-in normalisation.