ruby-on-rails - 用于 strip 化非字母和非数字字符的正则表达式

Question

这里是编程新手。在 ruby​​ 中，我将如何对以下非字母和非数字字符的字符串进行 strip 化处理，然后通过空格将其拆分为一个数组。

例子

string = "Honey - a sweet, sticky, yellow fluid made by bees and other insects from nectar collected from flowers."

进入这个

tokenized_string = ["Honey", "a", "sweet", "sticky", "yellow", "fluid", "made", "by", "bees", "and", "other", "insects", "from", "nectar", "collected", "from", "flowers"]

如有任何帮助，我们将不胜感激!

Answer 1

我会使用:

string = "Honey - a sweet, sticky, yellow fluid made by bees and other insects from nectar collected from flowers."
string.delete('^A-Za-z0-9 ').split 
# => ["Honey",
#     "a",
#     "sweet",
#     "sticky",
#     "yellow",
#     "fluid",
#     "made",
#     "by",
#     "bees",
#     "and",
#     "other",
#     "insects",
#     "from",
#     "nectar",
#     "collected",
#     "from",
#     "flowers"]

如果您尝试删除除字母数字以外的所有内容，则不能使用 \w 字符类，因为它被定义为 [A-Za-z0-9_]，它允许 _ 渗入或挤过。这是一个例子:

'foo_BAR12'[/\w+/] # => "foo_BAR12"

匹配整个字符串，包括_。

'foo_BAR12'[/[A-Za-z0-9]+/] # => "foo"

在 _ 处停止，因为类 [A-Za-z0-9] 不包含它。

\w 应被视为变量名称的匹配模式，而不是字母数字。如果您想要字母数字的字符类，请查看 POSIX \[\[:alnum:\]\]类:

'foo_BAR12'[/[[:alnum:]]+/] # => "foo"