python - 存储递归函数调用的值

Question

我正在递归调用函数obtainingparams，并要求residuals、tau_1和tau_2的值，在下面的代码中，每次调用都存储在某处，以便我可以比较与该函数的每次调用关联的值。但是，我不太确定如何去做这件事。

def obtainingparams(self, df, tau_1, tau_2, residuals):
    print('Calculate the yields Matrix and matrix_of_params in this part')

    params = np.linalg.lstsq(matrix_of_params,yields) 
    residuals = np.sqrt(((yields - matrix_of_params.dot(params))**2).sum())  
    tau_1 = tau_1 + 0.2 
    tau_2 = tau_2 + 0.2

    #Checkin how many times the function has been called via a decorator not included in this code
    while self.obtainingparams(self, df, tau_1, tau_2, residuals).called < 5:
        self.obtainingparams(self, df, tau_1, tau_2, residuals)

谢谢

Answer 1

您可以通过使用全局列表来完成此任务，但方式有点困惑。第一次调用的参数将在values[0]中，第二次调用的参数将在values[1]中，等等。

values = []

def obtainingparams(self, df, tau_1, tau_2, residuals):
    global values

    print('Calculate the yields Matrix and matrix_of_params in this part')

    params = np.linalg.lstsq(matrix_of_params,yields) 
    residuals = np.sqrt(((yields - matrix_of_params.dot(params))**2).sum())  
    tau_1 = tau_1 + 0.2 
    tau_2 = tau_2 + 0.2

    values.append((tau1, tau2, residuals))

    #Checkin how many times the function has been called via a decorator not included in this code
    while self.obtainingparams(self, df, tau_1, tau_2, residuals).called < 5:
        self.obtainingparams(self, df, tau_1, tau_2, residuals)

从设计的角度来看，如果您确实想跟踪每次调用所使用的参数，我不确定使用递归是否是最好的。