ios - 葫芦 iOS : how to get value using query command

Question

我正在尝试使用查询命令获取每个类的值。下面是我得到的示例 UI 组件:

[0] {
          "class" => "UITabBarSwappableImageView",
             "id" => "imageView-34",
           "rect" => {
        "center_x" => 288,
               "y" => 522,
           "width" => 48,
               "x" => 264,
        "center_y" => 538,
          "height" => 32
    },
          "frame" => {
             "y" => 2,
         "width" => 48,
             "x" => 6,
        "height" => 32
    },
          "label" => nil,
    "description" => "<UITabBarSwappableImageVie....>"

在 Android 上，我可以使用它来列出类组件的所有值:

query("*", :class)

但是，我似乎无法在 iOS 上使用相同的命令。结果是这样的:

irb(main):135:0> query "*", :class
[
    [ 0] nil,
    [ 1] nil,
    [ 2] nil,
    [ 3] nil
]

我知道有了标签，我可以使用 :accessibilityLabel 来完成这项工作，但当我尝试从 class/id/etc 获取值时则不行。

有人可以解释一下吗？

Answer 1

简短回答:'class' 不是 UIView 实例上的选择器

长答案:

# query( < look for some views >, < selector on the views found > )

# look for buttons marked 'big button' and call 'isSelected' selector on them
query("button marked:'big button'", :isSelected")

# look for labels marked 'title' and call 'text' selector on them
query("label marked:'title'", :text)

# look for all views and call 'class' selector on them
# whoops!  'class' is not a selector on UIView instances
query "*", :class

退后一步，我想我知道您要做什么 - 获取可见 View 的综合列表。

看看https://github.com/jmoody/briar/blob/master/lib/briar/irbrc.rb

示例输出在这里:https://gist.github.com/jmoody/8031917

不是在查询中调用“class”，而是遍历查询返回的结果并查找“class”键的值。

query('*').map { |result| result['class'] }