ruby - 按嵌套值对哈希排序

Question

我的散列如下所示。我希望输出采用相同的哈希形式，但哈希根据价格排列。

{
  1=>{
    "name"=>"Mark", 
    "date"=>"27/08/2015", 
    "bed"=>"3", 
    "furnish"=>"Fully", 
    "size"=>"10", 
    "price"=>790000
  }, 
  2=>{
    "name"=>"Mark", 
    "date"=>"27/08/2015", 
    "bed"=>"3", 
    "furnish"=>"Fully", 
    "size"=>"10", 
    "price"=>720000
  }, 
  3=>{
    "name"=>"Mark", 
    "date"=>"27/08/2015", 
    "bed"=>"3", 
    "furnish"=>"Fully", 
    "size"=>"10", 
    "price"=>750000
  }, 
  4=>{
    "name"=>"Mark", 
    "date"=>"27/08/2015", 
    "bed"=>"3", 
    "furnish"=>"Fully", 
    "size"=>"10", 
    "price"=>710000
  }
} 

我读过 How to sort a Ruby Hash by number value?但它只是一个嵌套的散列。我完全不知道如何实现这一目标。如果你们中有人愿意帮助我，我将不胜感激。

Answer 1

试试这个:

> myhash.sort_by{|_,v| v["price"]}.to_h
#=> 
    {
      4=>
        {
          "name"=>"Mark", 
          "date"=>"27/08/2015", 
          "bed"=>"3", 
          "furnish"=>"Fully", 
          "size"=>"10", 
          "price"=>710000
        }, 
      2=>
        {
          "name"=>"Mark", 
          "date"=>"27/08/2015", 
          "bed"=>"3", 
          "furnish"=>"Fully", 
          "size"=>"10", 
          "price"=>720000
        }, 
      3=>
        {
          "name"=>"Mark", 
          "date"=>"27/08/2015", 
          "bed"=>"3", 
          "furnish"=>"Fully", 
          "size"=>"10", 
          "price"=>750000
        }, 
      1=>
        {
          "name"=>"Mark", 
          "date"=>"27/08/2015", 
          "bed"=>"3", 
          "furnish"=>"Fully", 
          "size"=>"10", 
          "price"=>790000
        }
    } 

更新:

如果您的价格是 "15,000" 这样的字符串，那么您可以删除逗号分隔符并将其转换为整数，例如:

> "15,000"
> "15,000".tr(',', '').to_i
#=> 15000

所以代码是这样的:

> myhash.sort_by{|_,v| v["price"].tr(',', '').to_i}.to_h