Ruby 查找除周末以外的日期

Question

我想在您输入日期时生成一个 def get day。除了周末，我们每周工作 5 天。
例如:今天:27/02/2018
你输入:3 -> 输出:02/03/2018
你输入:5 -> 输出:06/03/2018
你输入:7 -> 输出:08/03/2018
你输入:10 -> 输出:13/03/2018

我的代码:

require 'date'

def next_week d, c
   return d + 7 * c
end

def my_add_day day
    d = Date.today
    d = next_week d, day/5
    day = day % 5
    if (6 - d.wday) > day
        d = d + day
    else
        d = d + day + 2
    end
    return d
end

你可以使用 gem https://github.com/bokmann/business_time

Answer 1

def add_working_days date, num
  num.times.inject(date) do |date|
    case date.wday
    when 5 then date + 3
    when 6 then date + 2
    else date + 1
    end
  end
end

main ▶ add_working_days Date.today, 3
#⇒ #<Date: 2018-03-02 ((2458180j,0s,0n),+0s,2299161j)>
main ▶ add_working_days Date.today, 5
#⇒ #<Date: 2018-03-06 ((2458184j,0s,0n),+0s,2299161j)>
main ▶ add_working_days Date.today, 7
#⇒ #<Date: 2018-03-08 ((2458186j,0s,0n),+0s,2299161j)>
main ▶ add_working_days Date.today, 10
#⇒ #<Date: 2018-03-13 ((2458191j,0s,0n),+0s,2299161j)>