python - 如何在 Python 中将另一个类的属性值设置为属性

Question

想象一下上课

class Bracings:  
     def __init__(self,type,axes,matrix):      
         self.type = type  
         self.axes = axes
         self.matrix = matrix

class Element:  
 ...

然后，想象一下

**elm** = *Element*()  
**br** = *Bracings*( 'buckling' , 'y', [1,2,3,4] )

我想要做的是在elm处创建一个像这样的属性

**elm**.bracing.buckling.y = **br**

问题是我不知道属性名称...它可能是buckling，它可能是later_tortional，它可能是y ，可能是 z 他们从 br 对象获取值

您将如何解决这个问题？

Answer 1

首先，您必须创建一个空的新类。那么你必须在 Element 上设置一个函数，如 set_bracings:

class Empty(object):  
    def __init__(self):  
        pass

#then at class Element:
class Element:
....
    def set_bracings(self, bracing):
        case = bracing.case
        axes = bracing.axes

        if hasattr(self,'bracings') == False:
            #Its the first ever bracing which is created
            empty1 = Empty()
            setattr( empty1, axes, bracing)
            empty2 = Empty()
            setattr( empty2, case, empty1)
            setattr( self, 'bracings', empty2)
        else:
           if hasattr(self.bracings,case) == False:
                #if we enter in this check then at some point another attribute of case was created, so we keep it
                brace = self.bracings

                empty1 = Empty()
                setattr( empty1, axes, bracing)
                setattr( brace, case, empty1)
                setattr( self, 'bracings', brace)
            else:
                #If we enter here then we our 'case' is the same as another 'case' that was created earlier so we have to keep it
                brace = self.bracings
                old_axes = getattr(self.bracings , case)
                setattr( old_axes, axes, bracing)
                setattr( brace, case, old_axes)
                setattr( self, 'bracings', brace)

#after that you only have to do
elm.set_bracings( br )