python - 从函数迭代字典

Question

我在从函数迭代字典时遇到问题。

def iteratedic():
    datadic={
    "one" : 1,
    "two" : 2,
    "three" : 3,
    "four" : 4
    }

    return datadic

def getdic():
    dictionary = iteratedic()
    for m, n in dictionary:
        print (m, n)

getdic()

它说

ValueError: too many values to unpack (expected 2)

Answer 1

您必须迭代 .items():

def iteratedic():
    datadic={
    "one" : 1,
    "two" : 2,
    "three" : 3,
    "four" : 4
    }

    return datadic

def getdic():
    dictionary = iteratedic()
    for m, n in dictionary.items():
        print (m, n)

getdic()

如果你打印dictionary，你会看到你得到{'four': 4, 'third': 3, 'two': 2, 'one': 1} .如果打印dictionary.items()，您将获得项目列表。 [('四', 4), ('三', 3), ('二', 2), ('一', 1)]。