c# - 3 个数组到 1 个 IEnumerable

Question

假设我有这个:

 public class test
 {
     int foo;
     int foo2;
     string foo3;
 }

 int[] foo = new int[] { 1, 2, 3 };
 int[] foo2 = new int[] { 4, 5, 6 };
 string[] foo3 = new string[] { "a", "b", "c" };

如何将这 3 个数组转换为测试的 IEnumberable？

TIA

/拉瑟

Answer 1

您可以使用 .NET 4.0 Enumerable.Zip 扩展方法:

foo.Zip(foo2, (first, second) => new { first, second })
    .Zip(foo3, (left, right) => new test
    {
        foo = left.first, 
        foo2 = left.second, 
        foo3 = right
    });

或者写一个方法来做这个:

public static IEnumerable<test> FooCombiner(int[] foo,
    int[] foo2, string[] foo3)
{
    for (int index = 0; index < foo.Length; index++)
    {
        yield return new test
        {
            foo = foo[index], 
            foo2 = foo2[index], 
            foo3 = foo3[index]
        };
    }
}

最后一个例子是最易读的 IMO。