c# - 编译我的程序时出现此错误。运算符 "+ "不能应用于 "System.Random"和 "System.Random"的操作数

Question

我正在尝试为数学问题生成随机数。编译程序时，错误运算符“+”不能应用于“System.Random”和“System.Random”类型的操作数。我真的不知道如何解决这个错误。

            Random num1 = new Random(0);                
            Random num2 =new Random(0); 
            int rand; 


            Console.Write("What is");
            Console.Write(num1);
            Console.Write( " - ");
            Console.Write( num2);
            Console.Write( "?");
            int answer = Console.Read();

                    if (num1 + num2 == answer) ERROR {
                    Console.Write(" Your are Correct!\n");
                    correctCount++;

                }
                    else
                    Console.Write( "Your answer is wrong" );
                    Console.Write(num1);
                    Console.Write(" + ");
                    Console.Write(num2);
                    Console.Write("should be ");
                    Console.Write(num1 + num2); ERROR
                    count++;
                }
            }

            }
        }

现在我可以毫无错误地编译程序，但它不会生成任何数字。有没有人看到我可能错了。

               using System;
               using System.Collections.Generic;
               using System.Linq;
               using System.Text;

               using Android.App;
               using Android.Content;
               using Android.OS;
               using Android.Runtime;
               using Android.Views;
               using Android.Widget;
             namespace Jagtutor
             {

[Activity(Label = "Addition")]
public class AdditionsActivity : Activity
{
    protected override void OnCreate(Bundle bundle)
    {
        base.OnCreate(bundle);
        // Create your application here
        SetContentView(Resource.Layout.Second);

        var label = FindViewById<TextView>(Resource.Id.screen3Label);
        label.Text = Intent.GetStringExtra("ModuleData") ?? "Data not available";

        {
        int correctCount = 0;
        int count = 0;

             while (count < 10);
            {
                Random gen = new Random();
                int num1 = gen.Next();
                int num2 = gen.Next(); 


            Console.Write("What is");
            Console.Write(num1);
            Console.Write( " - ");
            Console.Write( num2);
            Console.Write( "?");
            int answer = Int32.Parse(Console.ReadLine());

                    if (num1 + num2 == answer) {
                    Console.Write(" Your are Correct!\n");
                    correctCount++;

                }
                    else
                    Console.Write( "Your answer is wrong" );
                    Console.Write(num1);
                    Console.Write(" + ");
                    Console.Write(num2);
                    Console.Write("should be ");
                    Console.Write(num1 + num2);
                    count++;
                }
            }

            }
        }

Answer 1

你误解了Random的使用方式:它不是一个数字，它是一个可以用来生成随机数的类.

试试这个:

// Make a generator
Random gen = new Random();
// Now we can use our generator to make new random numbers like this:
int num1 = gen.Next();       
int num2 = gen.Next();       

每次调用 gen.Next() 都会得到一个新的随机数。如果您希望随机数序列是可重复的，请将一个数字(任何数字)传递给 Random 的构造函数。请注意，每次运行程序时，结果都将保持不变。