c# - 为什么第二个 IF 语句检测到无法访问的代码？

Question

TaskCompletionSource<bool> sy;
        public string SendResponse(HttpListenerRequest request)
        {
            string result = "";
            string key = request.QueryString.GetKey(0);
            if (key == "cmd")
            {
                if (request.QueryString[0] == "upload status")
                {
                    if (Youtube_Uploader.fileuploadstatus == "uploading file")
                    {
                        Youtube_Uploader.fileuploadstatus = "";
                        return "uploading";
                    }
                    else
                    {
                        return "upload unknown state";
                    }

                    if (Youtube_Uploader.fileuploadstatus == "file uploaded successfully")
                    {
                        Youtube_Uploader.fileuploadstatus = "";
                        return "upload completed";
                    }
                    else
                    {
                        return "upload unknown state";
                    }
                }
                if (request.QueryString[0] == "nothing")
                {
                    return "Connection Success";
                }
                if (request.QueryString[0] == "start")
                {
                    StartRecrod();
                    result = "Recording started";
                }

                if (request.QueryString[0] == "stop")
                {
                    dirchanged = false;
                    StartRecrod();
                    result = "Recording stopped and preparing the file to be shared on youtube";
                    sy = new TaskCompletionSource<bool>();
                    WatchDirectory();
                    sy.Task.Wait();
                    Youtube_Uploader youtubeupload = new Youtube_Uploader(fileforupload);

                }
            }
            else
            {
                result = "Nothing have been done";
            }

            return result;

        }

这一行:

if (Youtube_Uploader.fileuploadstatus == "file uploaded successfully")

'if' 带有绿色下划线，表示检测到无法访问的代码。我该如何修复它以及为什么它是无法访问的代码？

也许我需要使用 result = 而不是 return ？但这似乎不是问题所在。

Answer 1

因为除此之外，您还有:

if (...)
{
    return "uploading";
}
else
{
    return "upload unknown state";
}

if 或 else 为真，因此代码无论如何都会从该 block 返回，并且不会执行其下面的代码。

你有三个选项，所以你似乎在寻找一个 switch ，在这种情况下它是最易读的:

switch (Youtube_Uploader.fileuploadstatus)
{   
    case "uploading file":
        Youtube_Uploader.fileuploadstatus = "";
        return "uploading";

    case "file uploaded successfully":
        Youtube_Uploader.fileuploadstatus = "";
        return "upload completed";

    default:
        return "upload unknown state";
}

或者使用字典将服务状态转换为您的应用程序状态，或者按照@Thiago 的建议使用if () else if () else .