ruby - 这个计算元音的 Ruby 程序有什么问题？

Question

当我在字符串上测试这个程序时，输出为 0。我认为我的逻辑是合理的，它只是一个次要的语法问题。有人看到问题了吗？

def VowelCount(string)

  string.downcase
  i = 0
  vowels = 0

  until i == string.length-1
    if (string[i] == "a" || string[i] == "o" || string[i] == "e" || string[i] == "i" || string[i] == "u")
      vowels += 1
      end
    i += 1
    end
  return vowels
  end

Answer 1

您可以使用 String#count :

str = "It was the best of times, it was the worst of times,..."

str.downcase.count('aeiou') #=> 14