Python 和 Pyinstaller : include binary application in code

Question

我有一个小应用程序。为了保护我使用 c:/hwid.exe。应用程序返回 PC 的 HWID。示例代码:

def HWID_LIC():
    try:
        if hashlib.md5(open('c:\hwid.exe', 'rb').read()).hexdigest() != 'bca173dc':
            sys.exit(1)
        out = os.popen("c:\hwid.exe").read().strip()
        if out not in lic:
            sys.exit(1)
    except:
        sys.exit(1)

HWID_LIC()

我想将 hwid.exe 包含在我的应用程序中，并且需要将解决方案全部包含在一个文件中。在 Python 中可以做到这一点吗？ hwid.exe 有 30 kb。

Answer 1

这是可能的。您需要在sys._MEIPASS中搜索您的hwid.exe

import sys
import os
import hashlib

def HWID_LIC():
    if os.path.isfile('hwid.exe'):
        print('file found in .')
    else:
        print('file not found in .')

    if os.path.isfile(sys._MEIPASS + os.sep + 'hwid.exe'):
        print('file found in sys._MEIPASS')
    else:
        print('file not found')
    print(hashlib.md5(open(sys._MEIPASS + os.sep + 'hwid.exe', 'rb').read()).hexdigest())


if __name__ == '__main__':
    HWID_LIC()

示例规范文件:

# -*- mode: python -*-
a = Analysis(['test.py'],
             pathex=[],
             hiddenimports=[],
             runtime_hooks=None)
import platform
if platform.system().find("Windows")>= 0:
    a.datas = [i for i in a.datas if i[0].find('Include') < 0]
a.binaries = [x for x in a.binaries if not x[0].startswith("scipy")]
a.binaries = [x for x in a.binaries if not x[0].startswith("numpy")]
a.datas += [('hwid.exe','.\\hwid.exe','DATA'),]
pyz = PYZ(a.pure)
exe = EXE(pyz,
          a.scripts,
          a.binaries,
          a.zipfiles,
          a.datas,
          name='test.exe',
          debug=False,
          strip=None,
          clean=True,
          upx=False,
          console=True)

并创建 onefile exe

pyinstaller t_onefile.spec

执行 test.exe 时您会看到:

j:\tmp>test.exe
file not found in .
file found in sys._MEIPASS
754222d71581010a45732c471437ecf7