python - 如何从 django Rest Frameworks 基于类的创建 View 将对象添加到我的用户配置文件上的 M2M 字段？

Question

我正在尝试让登录用户将媒体添加到 DRF 通用创建 View 中用户配置文件的媒体字段中。有人试过这个吗？这是我的观点和模型:

class MediaCreate(generics.CreateAPIView):
"""
    To create a media object, send a post request to:
        /profiles/media/create/
    In the format:
        Audio: "audio file upload"
        Title: "char field"
"""
queryset = Media.objects.all()
serializer_class = MediaSerializer



class Musician(ProfileModel):
    summary = models.TextField(blank=True)
    company = models.CharField(max_length=60, blank=True)
    media = models.ManyToManyField('Media', blank=True)
    timestamp = models.DateTimeField(auto_now_add=True, blank=True)


def __str__(self):
    return '{}'.format(self.user.username)

Answer 1

所以我决定使用函数 api View 来完成此操作，这样我就可以使用请求将模型添加到配置文件中，而不需要任何 get 请求我知道检查 if 方法 == Post 是多余的，但它不会造成任何损害:

   @api_view(['POST'])
   def MediaCreate(request):
       context = {}
       logged_on = False
       if request.user.is_authenticated():
          logged_on = True
          visitor = request.user.musician
          serializer = MediaSerializer(data=request.data)
          if request.method == "POST":
              if serializer.is_valid():
                 serializer.save()
                 try:
                    x = serializer.instance
                    visitor.media.add(x)
                    context['upload'] = True
                 except:
                    error = "Media Not Added to Profile"
                    context['logged_on', 
                             'error', 
                              'upload'] = logged_on, error, False
                    return JsonResponse(
                                      data=context,
                                  status=status.HTTP_400_BAD_REQUEST)
      context['logged_on'] = logged_on
      return JsonResponse(data=context, status=status.HTTP_200_OK)