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python - Django Rest 框架 URL 模式

转载 作者:太空宇宙 更新时间:2023-11-03 17:00:26 40 4
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所以我只是摆弄 Django Rest 框架并尝试安装 oauth2。我可以有 2 个 url 模式吗,比如下面的 url.py 还是应该像这样:

urlpatterns = [
url(r'^$', 'memories_app.views.home', name='home'),
url(r'^admin/', admin.site.urls),
url(r'^o/', include('oauth2_provider.urls', namespace='oauth2_provider')),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework'))
url(r'^', include(router.urls)),
]

当我这样做时,我收到错误:

url(r'^', include(router.urls)), ^

SyntaxError: invalid syntax and my site wont load.

urls.py

 from django.conf import settings
from django.conf.urls import include, url
from django.conf.urls.static import static
from django.contrib import admin
from django.conf.urls import patterns, url
from django.core.urlresolvers import reverse
from django.contrib.auth.models import User
from rest_framework import routers, serializers, viewsets

urlpatterns = [
url(r'^$', 'memories_app.views.home', name='home'),
url(r'^admin/', admin.site.urls),
url(r'^o/', include('oauth2_provider.urls', namespace='oauth2_provider')),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework'))
]


# Serializers define the API representation.
class UserSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = User
fields = ('url', 'username', 'email', 'is_staff')

# ViewSets define the view behavior.
class UserViewSet(viewsets.ModelViewSet):
queryset = User.objects.all()
serializer_class = UserSerializer

# Routers provide an easy way of automatically determining the URL conf.
router = routers.DefaultRouter()
router.register(r'users', UserViewSet)

# Wire up our API using automatic URL routing.
# Additionally, we include login URLs for the browsable API.
urlpatterns = [
url(r'^', include(router.urls)),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework'))
]

最佳答案

您忘记了 router.urls 行之前的逗号。正确的 block 应该是:

urlpatterns = [
url(r'^$', 'memories_app.views.home', name='home'),
url(r'^admin/', admin.site.urls),
url(r'^o/', include('oauth2_provider.urls', namespace='oauth2_provider')),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework')), # Here
url(r'^', include(router.urls)),
]

关于python - Django Rest 框架 URL 模式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35049801/

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