php - 如何在Python中解码使用gzip压缩的源代码

Question

我正在尝试使用代理获取 php 网页的源代码，但它显示不可打印的字符。我得到的输出如下:

 "Date: Tue, 09 Feb 2016 10:29:14 GMTServer: Apache/2.4.9 (Unix) OpenSSL/1.0.1g PHP/5.5.11 mod_perl/2.0.8-dev Perl/v5.16.3X-Powered-By: PHP/5.5.11Set-Cookie: PHPSESSID=jmqasueos33vqoe6dbm3iscvg0; path=/Expires: Thu, 19 Nov 1981 08:52:00 GMTCache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0Pragma: no-cacheContent-Encoding: gzipVary: Accept-EncodingContent-Length: 577Keep-Alive: timeout=5, max=99Connection: Keep-AliveContent-Type: text/html�TMo�@�G����7�)P�H�H�DS��=U�=�U�]˻��_�Ycl�T�*�>��eg��                                                          ����Z�                                                                �V�N�f�:6�ԫ�IkZ77�A��nG�W��ɗ���RGY��Oc`-ο�ƜO��~?�V��$�                            �l4�+���n�].W��TLJSx�/|�n��#���>��r����;�l����H��4��f�\  �SY�y��7��" 

如何使用 python 解码此代码，我尝试使用

decd=zlib.decompress(data, 16+zlib.MAX_WBITS) 

但没有给出解码数据

我正在使用的代理对于其他一些网络应用程序来说工作得很好。它显示某些 Web 应用程序的不可打印字符，如何解码？

由于我使用代理，我不想使用 get() 和 urlopen() 或来自 python 程序的任何其他请求。

Answer 1

一种明显的方法是从响应中提取压缩数据并使用GzipFile().read()对其进行解压缩。这种分割响应的方法可能容易失败，但情况如下:

from gzip import GzipFile
from StringIO import StringIO

http = 'HTTP/1.1 200 OK\r\nServer: nginx\r\nDate: Tue, 09 Feb 2016 12:02:25 GMT\r\nContent-Type: application/json\r\nContent-Length: 115\r\nConnection: close\r\nContent-Encoding: gzip\r\nAccess-Control-Allow-Origin: *\r\nAccess-Control-Allow-Credentials: true\r\n\r\n\x1f\x8b\x08\x00\xa0\xda\xb9V\x02\xff\xab\xe6RPPJ\xaf\xca,(HMQ\xb2R()*M\xd5Q\x00\x89e\xa4&\xa6\xa4\x16\x15\x03\xc5\xaa\x81\\\xa0\x80G~q\t\x90\xa7\x94QRR\x90\x94\x99\xa7\x97_\x94\xae\x04\x94\xa9\x85(\xcfM-\xc9\xc8\x07\x99\xa0\xe4\xee\x1a\xa2\x04\x11\xcb/\xcaL\xcf\xcc\x03\x89\x19Z\x1a\xe9\x19\x9aY\xe8\x19\xea\x19*q\xd5r\x01\x00\r(\xafRu\x00\x00\x00'

body = http.split('\r\n\r\n', 1)[1]
print GzipFile(fileobj=StringIO(body)).read()

输出

{  "gzipped": true,   "headers": {    "Host": "httpbin.org"  },   "method": "GET",   "origin": "192.168.1.1"}

If you feel compelled to parse the full HTTP response message, then, as inspired by this answer, here is a rather roundabout way to do it which involves constructing a httplib.HTTPResponse directly from the raw HTTP response, using that to create a urllib3.response.HTTPResponse, and then accessing the decompressed data:

import httplib
from cStringIO import StringIO
from urllib3.response import HTTPResponse

http = 'HTTP/1.1 200 OK\r\nServer: nginx\r\nDate: Tue, 09 Feb 2016 12:02:25 GMT\r\nContent-Type: application/json\r\nContent-Length: 115\r\nConnection: close\r\nContent-Encoding: gzip\r\nAccess-Control-Allow-Origin: *\r\nAccess-Control-Allow-Credentials: true\r\n\r\n\x1f\x8b\x08\x00\xa0\xda\xb9V\x02\xff\xab\xe6RPPJ\xaf\xca,(HMQ\xb2R()*M\xd5Q\x00\x89e\xa4&\xa6\xa4\x16\x15\x03\xc5\xaa\x81\\\xa0\x80G~q\t\x90\xa7\x94QRR\x90\x94\x99\xa7\x97_\x94\xae\x04\x94\xa9\x85(\xcfM-\xc9\xc8\x07\x99\xa0\xe4\xee\x1a\xa2\x04\x11\xcb/\xcaL\xcf\xcc\x03\x89\x19Z\x1a\xe9\x19\x9aY\xe8\x19\xea\x19*q\xd5r\x01\x00\r(\xafRu\x00\x00\x00'

class DummySocket(object):
    def __init__(self, data):
        self._data = StringIO(data)
    def makefile(self, *args, **kwargs):
        return self._data

response = httplib.HTTPResponse(DummySocket(http))
response.begin()
response = HTTPResponse.from_httplib(response)
print(response.data)

输出

{  "gzipped": true,   "headers": {    "Host": "httpbin.org"  },   "method": "GET",   "origin": "192.168.1.1"}