python - 将列表项打印为整数

Question

所以我有一些代码可以读取包含这种格式的分数的文件:

lenard  1 
max 1
lenard  1
max 5
zack    3
max 4
james   4
zack    3
zack    3
james   4
eddie   7
james   4
eddie   7
eddie   7
lenard  4
lenard  10

我的代码可以获取每个名称的最高分，并从最高到最低输出:

data = {}
alpha={}
with open('StudentsScoreA.txt') as fobj:
    for line in fobj:           #
        name, score = line.split()
        data.setdefault(name, []).append(int(score))

for name, scores in sorted(data.items()):
    highest = scores[-1:]
    alpha.update({name:highest})
    print(alpha)

for x in sorted(alpha, key=alpha.get, reverse=True):
    print('{} your score was {}'.format(x, alpha[x))

程序可以运行，但输出不正确:

lenard your score was [10]
eddie your score was [7]
max your score was [4]
james your score was [4]
zack your score was [3]

我想知道如何让它打印出来:

lenard your score was 10

我确实尝试通过这样做来做到这一点:

highest = ''.join(str(item) for item in highest)

虽然这确实输出得更好，但程序不会按排序顺序打印出来。我该如何解决？

Answer 1

使用[-1]代替[-1:]切片语法(在列表中)将始终返回一个列表

[1,2,3,4] [-1] => 4

for name, scores in sorted(data.items()):
    highest = scores[-1] #was scores[-1:]
    alpha.update({name:highest})
    print(alpha)