python - 尝试将邮政编码转换为二进制时找不到错误

Question

这是我的代码，我觉得这应该可以工作。我刚才添加了 zipcode = str(zipcode) 来看看它是否可以工作，但它没有，所以我可能会把它拿出来，让原始的邮政编码成为一个字符串。我需要它是一个字符串，因为我不希望二进制数字实际相加。当我在 python shell 中初始化该函数时，它什么也不返回

def digitConvert(zipcode):
zipcode = str(zipcode)
n = 0
binary = ""
while n < len(zipcode):
    if zipcode[n] == 0:
        binary = binary + "11000"
        n = n + 1
    elif zipcode[n] == 1:
        binary = binary + "00011"
        n = n + 1
    elif zipcode[n] == 2:
        binary = binary + "00101"
        n = n + 1
    elif zipcode[n] == 3:
        binary = binary + "00110"
        n = n + 1
    elif zipcode[n] == 4:
        binary = binary + "01001"
        n = n + 1
    elif zipcode[n] == 5:
        binary = binary + "01010"
        n = n + 1
    elif zipcode[n] == 6:
        binary = binary + "01100"
        n = n + 1
    elif zipcode[n] == 7:
        binary = binary + "10001"
        n = n + 1
    elif zipcode[n] == 8:
        binary = binary + "10010"
        n = n + 1
    elif zipcode[n] == 9:
        binary = binary + "10100"
        n = n + 1
return binary

感谢您的帮助!

Answer 1

如果我理解正确的话，邮政编码是一个整数。这是一个将整数转换为二进制的 python 小函数。默认是您想要 24 位二进制。

def int2bin(n, count=24):
    """returns the binary of integer n, using count number of digits"""
    return "".join([str((n >> y) & 1) for y in range(count-1, -1, -1)])

例如，我的邮政编码是 60517，所以我会这样做:

>>> print int2bin(60517)  
000000001110110001100101 

如果我只想要 16 个二进制位:

>>> print int2bin(60517, 16)
1110110001100101