Python Selenium 如何单击特定文本旁边的按钮？

Question

<div class = "Repo List">
    <div class = "Repo">
        <div class = "Text">
            <span class = "Display Text">Repo1</span>
        </div>
        <div class = "Button">
            <div class = "Click Button">Delete</div>
        </div>
    </div>

    <div class = "Repo">
        <div class = "Text">
            <span class = "Display Text">Repo2</span>
        </div>
        <div class = "Button">
            <div class = "Click Button">Delete</div>
        </div>
    </div>

    <div class = "Repo">
        <div class = "Text">
            <span class = "Display Text">Repo3</span>
        </div>
        <div class = "Button">
            <div class = "Click Button">Delete</div>
        </div>
    </div>
</div>

上面的代码中我想点击删除按钮，问题是每次添加一个Repo时，该repo的类名、显示文本的类名、删除按钮的类名是除了存储库显示名称之外，所有存储库都相同。

我想做的就是单击特定存储库名称旁边的删除按钮。我尝试了 .//span[text() = "RepoName"] 但这仅检测到存储库名称，而不检测到它旁边的按钮。

我对 Selenium 还很陌生，我对如何去做感到困惑。

Answer 1

如果您想要某个 RepoX 之后的按钮 div，请找到跨度并使用 Button 类获取以下 div:

.xpath("//span[text()='Repo3']/following::div[@class='Button']")

如果您不知道类名，但知道它是下一个 div:

 .xpath("//span[text()='Repo3']/following::div[1]")