ruby - 更新 ruby​​ 中的哈希段

Question

我有这样的哈希:

fields = {
  '0' => {
    'field' => 'something',
    'field_type' => 'something type',
    'validation' => { 'enabled' => 'true', 'persisted' => 'false', 'another thing' => 'false' }
  },
  '1' => {
    'field' => 'something else',
    'field_type' => 'something else type',
    'validation' => { 'enabled' => 'true', 'persisted' => 'false' }
  }
}

在上面的散列中， bool 值是字符串。我希望它们是 bool 值。也可能有许多键/值对，但值将始终为“真”或“假”。这是我的解决方案:

fields
 => {"0"=>{"field"=>"something", "field_type"=>"something type", "validation"=>{"enabled"=>"true", "persisted"=>"false", "another thing"=>"false"}}, "1"=>{"field"=>"something else", "field_type"=>"something else type", "validation"=>{"enabled"=>"true", "persisted"=>"false"}}} 
 copy = fields.reduce({}) do |acc,(k,v)|
   acc[k] = {
     'fields' => v['field'],
     'field_type' => v['field_type'],
     'validation' => v['validation'].reduce({}) {|acc,(k,v)| acc[k] = (v == "true" ) ? true : false; acc; }
   }
   acc
 end
  => {"0"=>{"fields"=>"something", "field_type"=>"something type", "validation"=>{"enabled"=>true, "persisted"=>false, "another thing"=>false}}, "1"=>{"fields"=>"something else", "field_type"=>"something else type", "validation"=>{"enabled"=>true, "persisted"=>false}}} 

它有效，但我的直觉是它很慢而且有问题。是否有更有效的方法来执行此操作，也许是内联(无需创建副本)？

Answer 1

这将修改哈希内联:

fields.each do |record, data|
  data.each do |field, value|
    next unless value.is_a?(Hash)
    value.each do |subkey, subvalue|
      fields[record][field][subkey] = subvalue == 'true'
    end
  end
end

基本上，只需遍历每个散列，但将键存储在每个嵌套级别，这样您就可以直接在最内层循环中分配值。