Python线程: How to build a dictionary from the results

Question

我将以下代码嵌套在另一个函数中(因此这不是任何类型的独立文件):

train_set_percentages = [0.2,0.5,0.8,1.0]
results = {}

for i in range(len(train_set_percentages)):
    kf2_index_percent,kf5_index_percent,loo_index_percent = generate_data_entry(train_set_percentages[i])
    results[kf2_index_percent[0]] = kf2_index_percent[1]
    results[kf5_index_percent[0]] = kf5_index_percent[1]
    results[loo_index_percent[0]] = loo_index_percent[1]

generate_data_entry 返回三个元组，kf2_index...等。我需要最终字典中的所有元组(键，数据)。

我有:

import threading
from threading import Thread

但是，我不知道如何从函数的输出构建这个字典。只有 5 个训练集百分比，那么我如何并行运行它们并构建字典？

 for i in range(len(train_set_percentages)):
     Thread(target=generate_data_entry(train_set_percentages[i]))

然后...??

Answer 1

我在问题下方发布的链接中找到了解决方案。为了按照我上面描述的方式生成字典，

from threading import Thread

numbers = [1,2,3,4]
keys = ['one','two','three','four']

def add_to_dict(number,key,dict):
     dict[key] = number

n = 5 

dict_list = [{}] * 5
threads = [None] * 5

# run threads
for i in range(len(threads)):
    threads[i] = Thread(target=add_to_dict,args=(number[i],keys[i],dict_list[i]))
    threads[i].start()
for i in range(len(threads)):
    threads[i].join()

# merge dictionaries (using Python 3.5 syntax)
results = {}
for i in dict_list:
    results = {**results,**i}