python - 在 Django 中的 View 之间共享上下文？

Question

我有 3 个非常相似的 View 和模板的 View 。

我的代码变得重复，而且它似乎没有遵循 Django DRY 方法。

Views.py

@login_required
def registrations_check1_detail(request, registration_pk):

    registration = get_object_or_404(Registration, pk=registration_pk)

    costumer_profile_form = forms.CostumerProfileForm()

    # THIS CONTEXT IS REPEATED ACROSS  MANY OF MY VIEWS
    request_context = {
        'registration': registration,
        'status': Registration.STATUS_CHOICES,
        'costumer_profile_form': costumer_profile_form,
        'duration_form':  pf.DurationForm(),
        'REG_DURATION_CHOICES'  : Duration.REG_DURATION_CHOICES,
        'EXT_DURATION_CHOICES'  : Duration.EXT_DURATION_CHOICES,
        'is_editable': editable_fields_perm(request.user, registration)
    }

    return render(request, 'profiles/registrations_check1_detail.html', request_context)

@login_required
def finance_review_detail(request, registration_pk):

    costumer_profile_form = forms.CostumerProfileForm()

    registration = get_object_or_404(Registration, pk=registration_pk)

    request_context = {
        'registration': registration,
        'costumer_profile_form': costumer_profile_form,
        'duration_form':  pf.DurationForm(),
        'REG_DURATION_CHOICES'  : Duration.REG_DURATION_CHOICES,
        'EXT_DURATION_CHOICES'  : Duration.EXT_DURATION_CHOICES,
        'is_editable': editable_fields_perm(request.user, registration)
    }

    return render(request, 'profiles/finance_review_detail.html', request_context)

处理这个问题的正确方法是什么？

编辑

按照商王的建议，现在是这样的:

@login_required
def registration_detail(request, registration_pk):

    request_context = _registration_context(registration_pk, request.user)

    return render(request, 'profiles/registration_detail.html', request_context)

Answer 1

这很正常，但解决方案确实很简单，您可以将它们提取到一个函数中，只传递生成结果所需的参数，例如 costumer_profile_form、registration 在这种情况下。然后调用该函数就可以了。