c# - 使用正则表达式检索网络的 BSSID

Question

我运行以下命令来检索 BSSID 列表:

netsh wlan show networks mode=Bssid | findstr "SSID"

我得到了这个:

SSID 1 : John
    BSSID 1                 : b0:e7:54:f2:97:f9
SSID 2 : 2WIRE519
    BSSID 1                 : 00:1e:c7:fb:f5:89
SSID 3 : Home SCW
    BSSID 1                 : 00:1e:c7:fb:40:11
SSID 4 : CBV704W-AFE5
    BSSID 1                 : 00:1a:2b:57:2e:75
SSID 5 : neboi
    BSSID 1                 : 34:ef:44:76:e2:90

现在我想使用正则表达式存储个人 BSSID，我试试这个:

"^[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]$

...但不工作。谁能帮我这个？下面是一些示例代码:

string sPattern = "^[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]:[a-z0-9][a-z0-9]$";
            if (Regex.IsMatch(result, sPattern))
                Console.WriteLine("Pattern Found");
            else
                Console.WriteLine("Pattern Not Found");

Answer 1

试一试:

(?:[A-Fa-f0-9]{2}[:-]){5}(?:[A-Fa-f0-9]{2})