python - 我正在尝试创建一个地址簿程序，它将用户输入附加到其适当的列表中

Question

我无法将用户输入写入我的列表，我在这里做错了什么？这是我正在编写的一个地址簿程序，任务是创建并行列表，该列表将使用 for 或 while 循环将用户输入数据存储在适当的列表中。该程序还必须具有搜索功能，您可以在代码底部看到该功能。我遇到的问题是让程序将数据存储在我的列表中。不幸的是，列表给我带来了很多麻烦，无论我做了多少研究，我似乎都无法理解它。我遇到的问题是尝试将姓氏和名字写入我的姓名列表时的append.data函数。我做错了什么？

#NICHOLAS SHAFFER
#5/11/2016
#MYADDRESSBOOK

def menu():

    index = 0
    size = 100
    count = 0

    answer = raw_input("Are You Creating An Entry [Press 1] \nOr Are You Searching An Entry [Press 2] ")
    if answer == "1" : 
        print ("This is where we create")
        append_data(index, size, count)

    elif answer == "2" :
        print ("this is where we search")
        search_database()

    name[size]
    phone[size]
    addresss[size]


# IF we are creating 
def append_data(index, size, count):



    # collect information
    for index in range(0, 100):
        optOut = 'no'
        while optOut == 'no':
            lastname[count] = raw_input("What is the persons last name? ")
            firstname[count] = raw_input("What is the persons first name? ")
            phone[count] = raw_input("What id the persons phone number? ")  
            address[count] = raw_input("What is the persons address? ")
            count = count + 1
            print 'Would you like to create another entry?'
            optOut = raw_input('Would you like to create another entry? [ENTER YES OR NO]:')
        if optOut == 'yes':
            menu()


    #create string to print to file
    #print temp1
    #print (firstname + " " + lastname + ", " + phone + ", " + email + ", " + address) 

    print listName[index]
    print listPhone[index]
    print listAddress[index]
    print 'file has been added to your addressbook sucessfuly'
    menu()

# SEARCHING FOR A RECORD
def search_database():

    searchcriteria = raw_input("Enter your search Criteria, name? phone, or address etc ")
    print searchcriteria
    if searchcriteria == "name":
        temp1 = open(listName[lastname, firstname],"r")
        print temp1
    if searchcriteria == "phone":
        temp1 = open(listPhone[0], "r")
        print temp1
    if searchcriteria == "address":
        temp1 = open(listAddress[0], "r")
        print temp1
    else:
        print "sorry you must enter a valid responce, try again."
        menu()

    for line in temp1:
        if searchcriteria in line:
            print line
            errorMessage()

# USER DID NOT PICK CREATE OR SEARCH 
def errorMessage():
        print ("Incorrect Answer")
        exit()


menu()

Answer 1

您的错误消息说明了一切:

line 34, in append_data lastname[count]... NameError: global name 'lastname' is not defined

如果您在任何解释器中键入lastname[4]，您都会得到同样的错误——您只是从未定义过名为lastname的列表，因此您无法访问其中的项目。在短期内，你可以用一行来解决这个问题

lastname = list()

不过你最终会遇到更多麻烦； lastname 在您定义它的函数之外将无法访问，listName 也不会。我可能会通过将它们写入数据文件/数据库来实现这一点，或者创建一个快速类，其成员都可以访问 self.lastname。