python - 从 matplotlib `ax` 对象中提取刻度参数

Question

我希望能够使用 ax.tick_params 识别刻度线是否设置为“关闭”。有没有办法检查 ax 对象以查看它们是否已关闭？

import matplotlib.pyplot as plt

fig, ax = plt.subplots()

ax.spines['top'].set_visible(False)
ax.spines['bottom'].set_visible(False)
ax.spines['left'].set_visible(False)
ax.spines['right'].set_visible(False)


ax.tick_params(
    axis='both',  
    which='both',      

    bottom='off',     
    top='off',         
    left='off',
    right='off') 

# This is essentially what I want to be able to do
assert ax.xticks == 'off'

Answer 1

要迭代每个轴的刻度，您可以使用此代码

print "Major ticks of y axis"                                              
for tick in ax.yaxis.get_major_ticks():
    print tick.tick1On, tick.tick2On, tick.gridOn                                        
print "Minor ticks of y axis"
for tick in ax.yaxis.get_minor_ticks():
    print tick.tick1On, tick.tick2On, tick.gridOn   

要在 x 轴的刻度上导航，例如，只需替换

ax.yaxis.get_major_ticks()

由

ax.xaxis.get_major_ticks()

关于 Tick 对象的可公开访问的属性，请阅读此处:http://matplotlib.org/api/axis_api.html#matplotlib.axis.Tick