c# - C#有解析多层级联JSON的库吗？

Question

是否有一个库(首选 C#)来解决我称之为多级级联 JSON 的问题？

这是我的意思的一个例子:(伪代码/C#)

var json1 = @"{
    ""firstName"": ""John"",
    ""lastName"": ""Smith""
    }";

var json2 = @"{
    ""firstName"": ""Albert""
    }";

var json3 = @"{
    ""phone"": ""12345""
    }";

var cascadingJSON = JSON.Cascade(json1, json2, json3);

结果(与 CSS 行为相同)

{
    "firstName"": "Albert", /*Overridden*/
    "lastName"": "Smith", /*Inherited*/
    "phone"": "12345"   }"; /*Added*/
}

编辑 1 - 更复杂的示例

const string json1 =
                @"{
                     ""firstName"": ""John"",
                     ""lastName"": ""Smith"",
                     ""age"": 25,
                     ""address"": 
                     {
                         ""streetAddress"": ""21 2nd Street"",
                         ""city"": ""New York"",
                         ""state"": ""NY"",
                         ""postalCode"": ""10021""
                     },
                     ""phoneNumber"": 
                     [
                         {
                           ""type"": ""home"",
                           ""number"": ""212 555-1234""
                         },
                         {
                           ""type"": ""fax"",
                           ""number"": ""646 555-4567""
                         }
                     ]
                 }";

            const string json2 =
                @"{
                     ""firstName"": ""John2"",
                     ""lastName"": ""robert"",
                     ""age"": 25,
                     ""address"": 
                     {
                         ""state"": ""FL"",
                     },
                     ""phoneNumber"": 
                     [
                         {
                           ""type"": ""fax"",
                           ""number"": ""222 222-2222""
                         },
                         {
                           ""type"": ""iphone"",
                           ""number"": ""111 111-1111""
                         }
                     ]
                 }";

            const string json3 =
                @"{
                     ""firstName"": ""John3"",
                     ""father"": ""guy""
                 }";

            const string expectedResult =
                @"{
                     ""firstName"": ""John3"",
                     ""lastName"": ""robert"",
                     ""age"": 25,
                     ""father"": ""guy"",
                     ""address"": 
                     {
                         ""streetAddress"": ""21 2nd Street"",
                         ""city"": ""New York"",
                         ""state"": ""FL"",
                         ""postalCode"": ""10021""
                     },
                     ""phoneNumber"": 
                     [
                         {
                           ""type"": ""home"",
                           ""number"": ""212 555-1234""
                         },
                         {
                           ""type"": ""fax"",
                           ""number"": ""222 222-2222""
                         },
                         {
                           ""type"": ""iphone"",
                           ""number"": ""111 111-1111""
                         }
                     ]
                 }";

编辑2

在对需求进行更多思考之后，我发现更复杂的示例永远无法按原样运行。例如，级联功能无法知道某个电话号码是否已修改或是否为新号码。为了让它发挥作用，每个子实体都应该有一个唯一的标识符。

Answer 1

使用出色的 JSON.NET library 非常容易.此方法将对象与字符串、数字或对象的属性结合起来。

public static string Cascade(params string[] jsonArray)
{
    JObject result = new JObject();
    foreach (string json in jsonArray)
    {
        JObject parsed = JObject.Parse(json);
        foreach (var property in parsed)
            result[property.Key] = property.Value;
    }
    return result.ToString();
}

结果，给定你的例子:

{
  "firstName": "Albert",
  "lastName": "Smith",
  "phone": "12345"
}

---

根据您更新的问题进行编辑:

通过调整此解决方案以递归方式工作，您可以合并子对象。以下示例将匹配您的预期结果(数组除外)。您将能够轻松地扩展此解决方案，以类似于合并对象 (JObject) 的方式合并数组 (JArray)。

public static string Cascade(params string[] jsonArray)
{
    JObject result = new JObject();
    foreach (string json in jsonArray)
    {
        JObject parsed = JObject.Parse(json);
        Merge(result, parsed);
    }
    return result.ToString();
}

private static void Merge(JObject receiver, JObject donor)
{
    foreach (var property in donor)
    {
        JObject receiverValue = receiver[property.Key] as JObject;
        JObject donorValue = property.Value as JObject;
        if (receiverValue != null && donorValue != null)
            Merge(receiverValue, donorValue);
        else
            receiver[property.Key] = property.Value;
    }
}