ruby - 如何最好地包装 Ruby optparse 代码和输出？

Question

对于下面的代码，根据风格指南，它应该以 80 个字符换行:

opts.on('--scores_min <uint>', Integer, 'Drop reads if a single position in ',
                                        'the index have a quality score ',
                                        'below scores_main (default= ',
                                        "#{DEFAULT_SCORE_MIN})") do |o|
  options[:scores_min] = o
end

结果输出是:

    --scores_min <uint>          Drop reads if a single position in
                                 the index have a quality score
                                 below scores_main (default=
                                 16)

它以 72 个字符换行，看起来不对 :o(

我真的希望它包含 80 个字符并像这样对齐:

    --scores_min <uint>          Drop reads if a single position in the
                                 index have a quality score below
                                 scores_min (default=16)

如何巧妙地实现这一点？

Answer 1

在这种情况下最简单的解决方案是像这样堆叠参数:

opts.on('--scores_min <uint>',
        Integer, 
        "Drop reads if a single position in the ",
        "index have a quality score below ",
        "scores_min (default= #{DEFAULT_SCORE_MIN})") do |o|
  options[:scores_min] = o
end

这会产生一个相当令人愉快的输出:

    --scores_min <uint>          Drop reads if a single position in the 
                                 index have a quality score below 
                                 scores_min (default= 16)

更一般地说，here docs可以更轻松地以在代码和输出中看起来都不错的方式格式化输出字符串:

       # Deeply nested code
       puts <<~EOT
            Drop reads if a single position in the 
            index have a quality score below 
            scores_min (default= #{DEFAULT_SCORE_MIN})
       EOT

但在这种情况下效果不佳，因为描述字符串会自动缩进。