python - 连接到 nxt 砖时出错

Question

我正在使用 nxt-python 从我的树莓派连接到我的 nxt 砖。

经过一番与Python 3.2版本的蓝牙和USB库的斗争后，我已经设法让它通过蓝牙连接并要求输入密码。经过一番努力，我发现我可以在运行与 nxt 砖连接的 python 脚本之前在终端中输入 bluetooth-agent PASSKEY & (并将 PASSKEY 替换为 key )，据我所知效果很好。但现在它抛出一个错误。使用 USB 连接会引发不同的错误。

这是我使用两种方法(USB 和 BT)并启用调试时遇到的错误:

USB: True BT: True Fantom: False FUSB: False FBT: False
Traceback (most recent call last):
  File "/usr/local/lib/python3.2/dist-packages/nxt/locator.py", line 138, in find_one_brick
    if name and info[0].strip('\0') != name:
TypeError: Type str doesn't support the buffer API
Failed to connect to possible brick
Traceback (most recent call last):
  File "/usr/local/lib/python3.2/dist-packages/nxt/locator.py", line 131, in find_one_brick
    info = b.get_device_info()
  File "/usr/local/lib/python3.2/dist-packages/nxt/brick.py", line 27, in poll
    self.sock.send(ogram.bytes())
  File "/usr/local/lib/python3.2/dist-packages/nxt/bluesock.py", line 57, in send
    l0 = len(data.encode('utf-8')) & 0xFF
AttributeError: 'bytes' object has no attribute 'encode'
Failed to connect to possible brick
No brick was found.
    Is the brick turned on?
    For more diagnosing use the debug=True argument or
    try the 'nxt_test' script located in /bin or ~/.local/bin
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python3.2/dist-packages/nxt/locator.py", line 154, in find_one_brick
    raise BrickNotFoundError
nxt.locator.BrickNotFoundError

因为我了解 python，我可能可以通过编辑源代码来修复错误，但我担心我会破坏一些东西。我尝试过编辑它(保留我编辑的每个文件的备份)，然后它会超过几行，然后抛出另一个不同的错误。

编辑

当我尝试使用 python 2 导入时，它给了我这个错误:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python2.7/dist-packages/nxt/__init__.py", line 15, in <module>
    from nxt.locator import find_one_brick, Method
  File "/usr/local/lib/python2.7/dist-packages/nxt/locator.py", line 49
    if not silent: print("USB module unavailable, not searching there", file=sys.stderr)
                                                                            ^
SyntaxError: invalid syntax

Answer 1

我已经下载了 v2.2.2 稳定版本，而不是克隆主提交，它在 python2 下运行良好。可惜它不是 python3。